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disa [49]
3 years ago
11

calculate the percentage increase in speed of the cyclist when the power output changes from 200W to 300W

Physics
1 answer:
Likurg_2 [28]3 years ago
4 0

Answer:

50%

Explanation:

That would be the amount

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A typical neutron star may have a mass equal to that of the Sun but a radius of only 20 km.(a) What is the gravitational acceler
Pepsi [2]

Answer:

331665750000\ m/s^2

3257806.62409 m/s

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of Sun = 1.989\times 10^{30}\ kg

r = Radius of Star = 20 km

u = Initial velocity = 0

v = Final velocity

s = Displacement = 16 m

a = Acceleration

Gravitational acceleration is given by

g=\dfrac{GM}{r^2}\\\Rightarrow g=\dfrac{6.67\times 10^{-11}\times 1.989\times 10^{30}}{20000^2}\\\Rightarrow g=331665750000\ m/s^2

The gravitational acceleration at the surface of such a star is 331665750000\ m/s^2

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 331665750000\times 16+0^2}\\\Rightarrow v=3257806.62409\ m/s

The velocity of the object would be 3257806.62409 m/s

8 0
3 years ago
a 200 kg car is being pushed along a road with a force of 3000 Newtons and is receiving a frictional force of 300 Newtons. calcu
IgorLugansk [536]

Answer:

3500 po sagot eto na po ok

4 0
2 years ago
The density of the Earth is greater than the density of an equal volume of water by _____.
defon

Answer:

I think the second option is correct

please mark me as brainliest

5 0
3 years ago
Help me pls I need to turn this in quick!!!!
Vikki [24]

Answer:

C. When the waves overlap, they will cancel eanch other out and disappear

Explanation:

hope its help heart brainliest thnks

5 0
2 years ago
A cannon ball is shot horizontally off a 37.0 m cliff and lands a distance of 18.5 m
4vir4ik [10]

Answer:

vₓ = 6.73 m/s

Explanation:

  • Assuming no other external influences than gravity, in the horizontal direction (which we make to coincide with the x- axis) , speed is constant, so, applying the definition of average velocity, we can write the following equation:

       v_{x} = \frac{\Delta x}{\Delta t} (1)

  • Now, in the vertical direction (coincident with the y- axis) , as both movements are independent each other, initial velocity is zero, so we can write the following equation for the vertical displacement:

       \Delta h = \frac{1}{2} * g * t^{2} (2)

  • where Δh = -37.0 m , g = -9.8 m/s2
  • Solving (2) for t, we get:

       t = \sqrt{\frac{2*\Delta h}{g} } =\sqrt{\frac{2*37.0m}{9.8m/s2}} = 2.75 s (3)    

  • Taking t₀ = 0, ⇒ Δt = t
  • Replacing (3) in (1), we get:

       v_{x} = \frac{\Delta x}{\Delta t} = \frac{x}{t}  = \frac{18.5m}{2.75s} = 6.73 m/s

  • As the horizontal velocity is constant, the initial horizontal velocity is just the average one, i.e., 6.73 m/s.
5 0
3 years ago
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