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3 years ago

calculate the percentage increase in speed of the cyclist when the power output changes from 200W to 300W

Physics

1 answer:

Likurg_2 [28]3 years ago

4 0

Answer:

50%

Explanation:

That would be the amount

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A typical neutron star may have a mass equal to that of the Sun but a radius of only 20 km.(a) What is the gravitational acceler

Pepsi [2]

Answer:

$331665750000\ m/s^2$

3257806.62409 m/s

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of Sun = $1.989\times 10^{30}\ kg$

r = Radius of Star = 20 km

u = Initial velocity = 0

v = Final velocity

s = Displacement = 16 m

a = Acceleration

Gravitational acceleration is given by

$g=\dfrac{GM}{r^2}\\\Rightarrow g=\dfrac{6.67\times 10^{-11}\times 1.989\times 10^{30}}{20000^2}\\\Rightarrow g=331665750000\ m/s^2$

The gravitational acceleration at the surface of such a star is $331665750000\ m/s^2$

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 331665750000\times 16+0^2}\\\Rightarrow v=3257806.62409\ m/s$

The velocity of the object would be 3257806.62409 m/s

8 0

3 years ago

a 200 kg car is being pushed along a road with a force of 3000 Newtons and is receiving a frictional force of 300 Newtons. calcu

IgorLugansk [536]

Answer:

3500 po sagot eto na po ok

4 0

2 years ago

The density of the Earth is greater than the density of an equal volume of water by _____.

defon

Answer:

I think the second option is correct

please mark me as brainliest

5 0

3 years ago

Help me pls I need to turn this in quick!!!!

Vikki [24]

Answer:

C. When the waves overlap, they will cancel eanch other out and disappear

Explanation:

hope its help heart brainliest thnks

5 0

2 years ago

A cannon ball is shot horizontally off a 37.0 m cliff and lands a distance of 18.5 m

4vir4ik [10]

Answer:

vₓ = 6.73 m/s

Explanation:

Assuming no other external influences than gravity, in the horizontal direction (which we make to coincide with the x- axis) , speed is constant, so, applying the definition of average velocity, we can write the following equation:

$v_{x} = \frac{\Delta x}{\Delta t} (1)$

Now, in the vertical direction (coincident with the y- axis) , as both movements are independent each other, initial velocity is zero, so we can write the following equation for the vertical displacement:

$\Delta h = \frac{1}{2} * g * t^{2} (2)$

where Δh = -37.0 m , g = -9.8 m/s2
Solving (2) for t, we get:

$t = \sqrt{\frac{2*\Delta h}{g} } =\sqrt{\frac{2*37.0m}{9.8m/s2}} = 2.75 s (3)$

Taking t₀ = 0, ⇒ Δt = t
Replacing (3) in (1), we get:

$v_{x} = \frac{\Delta x}{\Delta t} = \frac{x}{t} = \frac{18.5m}{2.75s} = 6.73 m/s$

As the horizontal velocity is constant, the initial horizontal velocity is just the average one, i.e., 6.73 m/s.

5 0

3 years ago