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3 years ago

10

Which gas would you expect to have the fastest diffusion rate?

1 answer:

Readme [11.4K]3 years ago

6 0

A ammonia as it has the least molar mass

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What type of wave do the contractions of the snake muscles make as the snake moves forward

S_A_V [24]

Actually, there are four kinds of reptile motion:

Concertina - vermiform. Circular muscles around the snake squeeze the front of the snake's body out long, then the latter half is pulled forward.

Rectilinear crawling - Belly scutes are moved forward individually in a wave-like motion.

Side-winding - Snake's version of "walking". Use by several species to move over fluidic substrates, such as sand.

Lateral undulation - Most common form of movement. Snake presses on alternating pressure points to force body forward (or backward)

(taken from a user on Yahoo from Correct Answers)

3 0

3 years ago

Hydrazine (N 2 H 4 )) a rocket fuel reacts with oxygen to form nitrogen gas and water vapor . The reaction is represented with t

Drupady [299]

The mass of hydrazine (N₂H₄) required to produce 96 g of water (H₂O) is 85.4 g (Option C)

<h3>Balanced equation </h3>

N₂H₄ + O₂ —> N₂ + 2H₂O

Molar mass of N₂H₄ = (2×14) + (4×1) = 32 g/mol

Mass of N₂H₄ from the balanced equation = 1 × 32 = 32 g

Molar mass of H₂O = (2×1) + 16 = 18 g/mol

Mass of H₂O from the balanced equation = 2 × 18 = 36 g

SUMMARY

From the balanced equation above,

36 g of H₂O were produced by 32 g of N₂H₄

<h3>How to determine the mass of N₂H₄</h3>

From the balanced equation above,

36 g of H₂O were produced by 32 g of N₂H₄

Therefore,

96 g of H₂O will be produced by = (96 × 32) / 36 = 85.4 g of N₂H₄

Thus, 85.4 g of N₂H₄ is needed for the reaction

Learn more about stoichiometry:

brainly.com/question/14735801

8 0

2 years ago

Is this True or false?

kherson [118]

Answer:

true

Explanation:

7 0

3 years ago

Read 2 more answers

Two systems with heat capacities 19.9 J mol-1 K-1 and 28.2 ] mol 1 K-1 respectively interact thermally and come to an equilibriu

MAVERICK [17]

Answer : The initial temperature of system 2 is, $19.415^oC$

Explanation :

In this problem we assumed that the total energy of the combined systems remains constant.

$-q_1=q_2$

$m\times c_1\times (T_f-T_1)=-m\times c_2\times (T_f-T_2)$

The mass remains same.

where,

$C_1$ = heat capacity of system 1 = 19.9 J/mole.K

$C_2$ = heat capacity of system 2 = 28.2 J/mole.K

$T_f$ = final temperature of system = $30^oC=273+30=303K$

$T_1$ = initial temperature of system 1 = $45^oC=273+45=318K$

$T_2$ = initial temperature of system 2 = ?

Now put all the given values in the above formula, we get

$-19.9J/mole.K\times (303-318)K=28.2J/mole.K\times (303-T_2)K$

$T_2=292.415K$

$T_2=292.415-273=19.415^oC$

Therefore, the initial temperature of system 2 is, $19.415^oC$

8 0

3 years ago

Which equation is balanced?

Paha777 [63]

Answer:

it's the third one

Explanation:

in the first one oxygen molecules aren't balanced

the second ok me oxygen isnt balanced

and the fourth one hydrogen isn't balanced

hope it helps ;)

5 0

3 years ago

Read 2 more answers