Answer: A “system in exchange of matter with its environment, presenting import and export, building-up and breaking-down of its material components.”
Explanation:
The grams that would be produced from 7.70 g of butanoic acid and excess ethanol is 7.923grams
calculation
Step 1: write the chemical equation for the reaction
CH3CH2CH2COOH + CH3CH2OH → CH3CH2CH2COOCH2CH3 +H2O
step 2: find the moles of butanoic acid
moles= mass/ molar mass
= 7.70 g/ 88 g/mol=0.0875 moles
Step 3: use the mole ratio to determine the moles of ethyl butyrate
moles ratio of CH3CH2CH2COOH :CH3CH2CH2COOCH2CH3 is 1:1 therefore the moles of CH3CH2CH2COOCH2CH3 = 0.0875 x78/100=0.0683moles
step 4: find mass = moles x molar mass
= 0.0683 moles x116 g/mol=7.923grams
(a) benzene (C6H6) - <span>nonpolar molecules . Only dispersion forces are present.
</span>
(b) CH3Cl - <span>Chloroform ; polar molecules. Both dispersion and dipole-dipole forces are
present.
</span>
(c) PF3 - <span>Phosphorus triflouride ; has polar bonds but has nonpolar molecule due to its symmetrical structure. Only dispersion forces are present.
</span><span>
(d) NaCl - </span><span>Sodium chloride ; ionic compound. Both ion-ion and dispersion forces are present.</span><span>
(e) CS2 - </span><span>Carbon disulfide ; nonpolar molecules. Only dispersion forces are present.</span>
Answer:
the answer to the answer above is motion
