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aalyn [17]
3 years ago
9

A copper wire of resistivity 2.6 × 10-8 Ω m, has a cross sectional area of 35 × 10-4 cm2

Physics
1 answer:
KengaRu [80]3 years ago
6 0

Answer:

the length of the wire is 134.62 m.

Explanation:

Given;

resistivity of the copper wire, ρ = 2.6 x 10⁻⁸ Ωm

cross-sectional area of the wire, A  = 35 x 10⁻⁴ cm² = ( 35 x 10⁻⁴) x 10⁻⁴ m²

resistance of the wire, R = 10Ω

The length of the wire is calculated as follows;

R = \frac{\rho L}{A} \\\\L = \frac{RA}{\rho} \\\\L= \frac{10 \times (35\times 10^{-4}) \times 10^{-4}}{2.6 \times 10^{-8}} \\\\L = 134.62 \ m

Therefore, the length of the wire is 134.62 m.

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3 years ago
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A rock is lifted by a machine to a height of 10m. If it has a mass of 22 kilograms
zmey [24]

Answer:

2156J

Explanation:

Given parameters:

Height of lift  = 10m

Mass  = 22kg

Unknown:

Work done by the machine  = ?

Solution:

Work done is the force applied to move a body through a certain distance.

So;

        Work done  = Force x distance

Here;

       Work done  = mass x acceleration due to gravity x height

      Work done  = 22 x 9.8 x 10  = 2156J

5 0
3 years ago
As the mass of an object increases, the weight of the object will ______?
Sergio039 [100]

Answer:

also increase

Explanation:

If the mass increases so will the weight.

4 0
2 years ago
A man pushing a mop across a floor causes it to undergo two displacements. The first has a magnitude of 146 cm and makes an angl
svetlana [45]

Answer:

B = 191.26 cm

θ = -14.73°

Explanation:

given,

magnitude of the first displacement(A) = 146 cm

at an angle of 124°

resultant magnitude = 137 cm

and angle made with x-axis by the resultant(R) = 32.0°

component of A in X and Y direction

A x = A cos θ  = 146 cos 120° = -73 cm

A y = A sin θ = 146 sin 120° = 126.4 cm

now component of resultant in x and y direction

R x = 137 cos 35°

    = 112.2 cm

R y = 137 sin 35°

     = 78.6 cm

resultant is the sum of two vectors

R = A + B

R x = A x + B x

B x =  112.2 - (-73) = 185.2 cm

B y = R y - A y

B y = 78.6 - 126.4 = -47.8 cm

magnitude of B

B = \sqrt{B_x^2+B_y^2}

B = \sqrt{185.2^2+-47.8^2}

B = 191.26 cm

angle\theta = tan^{-1}\dfrac{-47.8}{185.2}

θ = -14.73°

6 0
3 years ago
Can anybody help me solve this problem? Thank you so much!
ser-zykov [4K]
Please ignore my comment -- mass is not needed, here is how to solve it. pls do the math

at bottom box has only kinetic energy
ke = (1/2)mv^2
v = initial velocity
moving up until rest work done = Fs
F = kinetic fiction force = uN = umg x cos(a)
s = distance travel = h/sin(a)
h = height at top
a = slope angle
u = kinetic fiction
work = Fs = umgh x cot(a)
ke = work (use all ke to do work)
(1/2)mv^2 = umgh x cot(a)
u = (1/2)v^2 x tan (a) / gh
4 0
3 years ago
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