Answer:
65 m/s north
Explanation:
The velocity of an object is given by:
![v=\frac{d}{t}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bd%7D%7Bt%7D)
where
d is the displacement of the object
t is the time interval needed for the displacement
For the rocket in this problem,
d = 390 m north
t = 6 s
So the velocity is
north
It is important to keep in mind that velocity is a vector, so it both has a magnitude (65 m/s) and a direction (which is equivalent to that of the displacement, so in this case north).
todas son unidades derivadas
Answer: i think thats the answer
≈
40.8
kg
Explanation:
Well, assuming the boy is on Earth, then the gravitational acceleration is approximately
9.8
m/s
2
.
So, we get:
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kgExplanation:
Answer:
![a=-1.388\ m/s^2](https://tex.z-dn.net/?f=a%3D-1.388%5C%20m%2Fs%5E2)
Explanation:
Initial velocity of car, u = 50 km/h = 13.88 m/s
It stops, v = 0
Time, t = 10 s
We need to find the car's deceleration while slowing down. As the car is slowing down, it will have deceleration. It can be calculated as follows :
![a=\dfrac{v-u}{t}\\\\a=\dfrac{0-13.88 }{10}\\\\a=-1.388\ m/s^2](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7Bv-u%7D%7Bt%7D%5C%5C%5C%5Ca%3D%5Cdfrac%7B0-13.88%20%7D%7B10%7D%5C%5C%5C%5Ca%3D-1.388%5C%20m%2Fs%5E2)
So, the deceleration of the car is
.