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In-s [12.5K]
4 years ago
12

How do you write the scientific name delis cactus correctly

Physics
2 answers:
Talja [164]4 years ago
8 0
Delis cactus is the correct way to write it.
stiks02 [169]4 years ago
3 0
Delis.cactus is the correct way
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What did the results of photoelectric-effect experiment establish?
Bond [772]

Answer:

Thanks For Points Mark Me Brainliest Please

Explanation:

Electrons are emitted as soon as low-intensity, high-frequency light hits a metal surface.

A. Is It

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4 years ago
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What is the magnitude of the gravitational force acting on the earth due to the sun?
expeople1 [14]

Answer: 3.524(10)^{22}N

Explanation:

According to Newton's law of Gravitation, the force F exerted between two bodies of masses m1 and m2  and separated by a distance r  is equal to the product of their masses and inversely proportional to the square of the distance:

F=G\frac{(m1)(m2)}{r^2}   (1)

Where:

G is the Gravitational Constant and its value is 6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}  

m1=1.99(10)^{30}kg is the mass of the Sun

m2=5.972(10)^{24}kg is the mass of the Earth

r=1.50(10)^{11}m  is the distance between the Sun and the Earth

Substituting the values in (1):

F=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(1.99(10)^{30}kg)(5.972(10)^{24}kg)}{(1.50(10)^{11}m)^2}   (2)

Finally:

F=3.524(10)^{22}N   This is the gravitational force acting on the earth due to the sun

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3 years ago
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When given a compound, adding up all of the _______ of all of the individual atoms within one molecule of a compound will determ
butalik [34]
Atomic masses should be about right 
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3 years ago
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Need help please and thank you​
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  • C
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Hope this helps you!!!

8 0
3 years ago
Initially (at time t = 0) a particle is moving vertically at 7.5 m/s and horizontally at 0 m/s. Its horizontal acceleration is 1
Lelu [443]

Answer:

t = 0.657 s

Explanation:

given,

initial vertical velocity = 7.5 m/s

initial horizontal velocity = 0 m/s

angle = 49◦

using kinetic equation

final velocity in vertical direction

v sinθ    = u_y   - gt ........................(1)

final velocity in horizontal direction

v cosθ = u_x   + a_x × t

here   u_x = 0.0 m/s

v cosθ = a_x×t ......................(2)

Dividing equation (1) / (2)

tan \theta =\dfrac{u_y - gt}{a_x\times t}

solving for time t

t = \dfrac{u_y}{tan \theta \times a_x + g}

u_y   =   initial velocity along x direction

acceleration along a_x = 1.4 m/s²

g = acceleration due to gravity   = 9.8 m/s²

θ = 43° ,   u_y   =  7.5 m/s    

t = \dfrac{7.5}{tan 49^0\times 1.4+ 9.8}

t = 0.657 s

time taken by the particle is t = 0.657 s

6 0
3 years ago
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