Answer:
B
Explanation:
Atomic structure contains electrons, protons and neutrons.
Electron is very light compared to proton and neutrons.
Given that the mass of an electron is
A) equal to the mass of a proton
B) less than the mass of a neutron
C) greater than the mass of a proton
D) equal to the mass of a neutron
The correct answer is B which is less than the mass of the neurons.
Answer:
w = 4,786 rad / s
, f = 0.76176 Hz
Explanation:
For this problem let's use the concept of angular momentum
L = I w
The system is formed by the two discs, during the impact the system remains isolated, we have the forces are internal, this implies that the external torque is zero and the angular momentum is conserved
Initial Before sticking
L₀ = 0 + I₂ w₂
Final after coupling
= (I₁ + I₂) w
The moments of inertia of a disk with an axis of rotation in its center are
I = ½ M R²
How the moment is preserved
L₀ =
I₂ w₂ = (I₁ + I₂) w
w = w₂ I₂ / (I₁ + I₂)
Let's reduce the units to the SI System
d₁ = 60 cm = 0.60 m
d₂ = 40 cm = 0.40 m
f₂ = 200 min-1 (1 min / 60 s) = 3.33 Hz
Angular velocity and frequency are related.
w₂ = 2 π f₂
w₂ = 2π 3.33
w₂ = 20.94 rad / s
Let's replace
w = w₂ (½ M₂ R₂²) / (½ M₁ R₁² + ½ M₂ R₂²)
w = w₂ M₂ R₂² / (M₁ R₁² + M₂ R₂²)
Let's calculate
w = 20.94 8 0.40² / (12 0.60² + 8 0.40²)
w = 20.94 1.28 / 5.6
w = 4,786 rad / s
Angular velocity and frequency are related.
w = 2π f
f = w / 2π
f = 4.786 / 2π
f = 0.76176 Hz
Look up pulleys problem through Khan academy and a video should pop up with a problem similar and you should be able to walk through it .
Answer:
14 N
Explanation:
The tension in the second string is puling both the masses of 20 kg and 8 kg with acceleration of 0.5 m s⁻²
So tension in the second string = total mass x acceleration
= 28 x .5 = 14 N . Ans..
(a) The ball’s maximum speed over the net is v(max) = √2gh.
(b) The maximum speed of the horizontally moving ball clearing the net is about 27 m/s.
(c) Speed of the ball is independent of its mass.
<h3>
Time of motion of the ball</h3>
The time of motion of the ball is calculated as follows;
h = vt + ¹/₂gt²
1 = 0 + ¹/₂(9.8)t²
1 = 4.9t²
t² = 1/4.9
t² = 0.204
t = 0.452 s
<h3>Horizontal speed of the ball</h3>
The horizontal speed of the ball is calculated as follows;
X = vt
v = X/t
v = (12 m)/(0.452)
v = 26.6 m/s ≈ 27 m/s (proved)
<h3>Conservation of energy</h3>
P.E = K.E
mgh = ¹/₂mv²
gh = ¹/₂v²
2gh = v²
√2gh = v(max)
Speed of the ball is independent of its mass.
Learn more about horizontal velocity here: brainly.com/question/24681896
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