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iogann1982 [59]
3 years ago
11

3. What range of numbers would you expect on the pH scale for an alkali? (1 mark)

Chemistry
2 answers:
Vikki [24]3 years ago
4 0

Answer:

a pH above 7 is alkali

a pH lower than 7 is acidic

Triss [41]3 years ago
3 0
I’m pretty sure it has to more than 7 (8 or 9)
You might be interested in
Calculate the vapor pressure at 25°C of a solution containing 55.3 g ethylene glycol (HOCH2CH2OH) and 285.2 g water. The vapor p
Snezhnost [94]

Answer:

Vapor pressure of solution = 23.9 Torr

Explanation:

Let's apply the colligative poperty of vapor pressure to solve this:

ΔP = P° . Xm

ΔP = Vapor pressure of pure solvent - Vapor pressure of solution

We have solvent and solute mass, so let's find out the moles of each.

55.3 g / 62 g/mol = 0.89 moles

285.2 g / 18 g/mol = 15.84 moles

Let's determine the mole fraction of ethylene glycol.

Mole fraction = Moles of ethylene glyco / Total moles

0.89 moles / (0.89 + 15.84) = 0.053

25.3 Torr - Vapor pressure of solution = 25.3 Torr . 0.053

Vapor pressure of solution = 25.3 Torr . 0.053 - 25.3 Torr

Vapor pressure of solution = 23.9 Torr

7 0
3 years ago
Read 2 more answers
How to find orbital notation?
AveGali [126]

Orbital notation is a way of writing an electron configuration to provide more specific information about the electrons in an atom of an element.

Orbital notation can be used to determine the quantum numbers of an electron.


6 0
3 years ago
The chemical formula for lithium fluoride is lif . a chemist determined by measurements that 0.035 moles of lithium fluoride par
Mnenie [13.5K]
Answer:
mass = 0.907865 grams

Explanation:
From the periodic table:
molar mass of Li = 6.941 grams
molar mass of F = 18.998 grams
Therefore:
molar mass of LiF = 6.941 + 18.998 = 25.939 grams/mole

number of moles can be calculated as follows:
number of moles = mass / molar mass
We have:
number of moles = 0.035 moles
molar mass = 25.939 grams/mole

Substitute in the equation to get the mass as follows:
0.035 = mass / 25.939
mass = 0.035 * 25.939 = 0.907865 grams

Hope this helps :)
3 0
3 years ago
Help please thank you!
Mrrafil [7]

Answer:....................................

Explanation:

5 0
3 years ago
A 25.0 liter rigid container has a mixture of 32.00 grams of oxygen gas and 1 point
Ksivusya [100]

Answer:

P_{T} = 2.94 atm

Explanation:

The total pressure (P_{T}) in the container is given by:

P_{T} = P_{O_{2}} + P_{He}

The pressure of the oxygen (P_{O_{2}}) and the pressure of the helium (P_{He}) can be calculated using the ideal gas law:

PV = nRT

<u>Where</u>:

V: is the volume = 25.0 L

n: is the number of moles of the gases

R: is the gas constant = 0.082 Latm/(Kmol)

T: is the temperature = 298 K

First, we need to find the number of moles of the oxygen and the helium:

n_{O_{2}} = \frac{m}{M}

Where m is the mass of the gas and M is the molar mass

n_{O_{2}} = \frac{32.00 g}{31.998 g/mol} = 1.00 moles  

And the number of moles of helium is:

n_{He} = \frac{8.00 g}{4.0026 g/mol} = 2.00 moles

Now, we can find the pressure of the oxygen and the pressure of the helium:

P_{O_{2}} = \frac{nRT}{V} = \frac{1.00 moles*0.082 Latm/(Kmol)*298 K}{25.0 L} = 0.98 atm

P_{He} = \frac{nRT}{V} = \frac{2.00 moles*0.082 Latm/(Kmol)*298 K}{25.0 L} = 1.96 atm

Finally, the total pressure in the container is:

P_{T} = P_{O_{2}} + P_{He} = 0.98 atm + 1.96 atm = 2.94 atm

Therefore, the total pressure in the container is 2.94 atm.

I hope it helps you!

6 0
4 years ago
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