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valina [46]
3 years ago
11

The 1350-kg car has a velocity of 24 km/h up the 8-percent grade when the driver applies more power for 18 s to bring the car up

to a speed of 65 km/h. Calculate the time average F of the total force tangent to the road exerted on the tires during the 18 s. Treat the car as a particle and neglect air resistance.
Physics
1 answer:
Brrunno [24]3 years ago
4 0

Answer:

Explanation:

We shall apply concept of impulse to solve the problem  .

Impulse = force x time

impulse = change in momentum

force x time = change in momentum

initial speed u = 24 km/h = 6.67 m /s

final speed v = 65 km/h = 18.05 m /s

change in momentum = m v - mu

= m ( v-u )

= 1350 ( 18.05 - 6.67 )

= 15363 kg m/s

F x 18 = 15363

F = 853.5 N .

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Vanyuwa [196]

The pressure exerted by this force is equal to 320 N/m^2.

<u>Given the following data:</u>

  • Force = 8000 Newton.
  • Area = 25 m^2.

To calculate the pressure exerted by this force:

<h3>How to calculate pressure.</h3>

Mathematically, pressure is given by this formula:

P=\frac{F}{A}

<u>Where:</u>

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Substituting the given parameters into the formula, we have:

P = \frac{8000}{25}

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Read more on pressure here: brainly.com/question/8033367

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2 years ago
Determine the length of the tungsten filament in a 100 watt lightbulb given: (i) the resistivity of tungsten is 5.6 × 10−8 Ω · m
svetoff [14.1K]

Answer:

0.34148 m

Explanation:

\rho = Resistivity of tungsten = 5.6\times 10^{-8}\ \Omega m

d = Diameter = 0.0018 inch

r = Radius = \dfrac{r}{2}=\dfrac{0.0018}{2}=0.0009\ in

r=0.0009\times 0.0254=0.00002286\ m

\alpha = Temperature coefficient of tungsten = 0.0045 /^{\circ}C

Power is given by

P=\dfrac{V^2}{R}\\\Rightarrow R=\dfrac{V^2}{P}\\\Rightarrow R=\dfrac{120^2}{100}\\\Rightarrow R=144\ \Omega

We have the equation

R_2=R_1[1+\alpha(T_2-T_1)]\\\Rightarrow R_1=\dfrac{R_2}{1+\alpha(T_2-T_1)}\\\Rightarrow R_1=\dfrac{144}{1+0.0045(2550-25)}\\\Rightarrow R_1=11.64812\ \Omega

Resistance is given by

R=\rho\dfrac{l}{A}\\\Rightarrow l=\dfrac{RA}{\rho}\\\Rightarrow l=\dfrac{11.64812\times \pi (0.00002286)^2}{5.6\times 10^{-8}}\\\Rightarrow l=0.34148\ m

The length of the filament is 0.34148 m

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Explanation:

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