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3 years ago

What is the SI unit of pressure? A. g/cm3 B. the pascal C. the newton D. m/s2

Physics

2 answers:

sesenic [268]3 years ago

6 0

The basic definition of pressure is force/area and the scientific community defined that as the Pascal (Pa).

Mekhanik [1.2K]3 years ago

5 0

N/m2 ............. may also be the answer youre looking for

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a child riding a bicycle at 15 meters per second accelerates at -3,0 meters per second? for 4.0 seconds. What is the child's spe

Vika [28.1K]

Answer:

Explanation:

Given data

initital velocity u=15m/s

deceleration a=3m/s^2

time t= 4 seconds

final velocity v= ?

Applying the expression

v=u+at------1

substituting our data into the expression we have

v=15+3*4

v=15+12

v=27m/s

The velocity after 4 seconds is 27m/s

5 0

3 years ago

The timeline below shows some major discoveries in biology.

34kurt

Answer:

The cell theory

Explanation:

3 0

3 years ago

Read 2 more answers

A block slides down an incline plane that makes a 30 degree angle with the

Alona [7]

Hi there!

We know that:

Force due to gravity = Mgsinθ

Force due to friction = μMgcosθ

Let the positive direction be directed in the direction of the block's acceleration, which is downward.

Thus:

ΣF = Mgsinθ - μMgcosθ

Solving for acceleration requires diving all terms by the mass, so:

a = gsinθ - μgcosθ

Substitute in given values. (g = 9.8 m/s²)

a = 9.8sin(30) - 0.3(9.8)cos(30) = 2.354 m/s²

7 0

3 years ago

The objective lens and the eyepiece of a telescope are spaced 85 cm apart. If the eyepiece is123 D what is the total magnificati

dedylja [7]

Answer:

The magnification would be "103.55". A further explanation is given below.

Explanation:

The given values are:

Distance between lens and eyepiece,

L = 85 cm

Eyepiece is,

= 123 D

Now,

The refractive power of eye piece will be:

⇒ $\frac{1}{f_e}=123D$

$f_e=\frac{1}{123D}$

$f_e=0.813 \ cm$

The length of the telescope will be:

⇒ $L=f_0+f_e$

⇒ $f_0=L-f_e$

On substituting the values, we get

⇒ $=85-0.813$

⇒ $=84.187 \ cm$

Now,

The magnification of the telescope will be:

⇒ $M=\frac{f_0}{f_e}$

⇒ $=\frac{84.187}{0.813}$

⇒ $=103.55$

5 0

2 years ago

You're designing an airport.A plane that will use this airport must reach a speed of Vmin=100km/h(27.8m/s).It can accelerate at

Ilia_Sergeevich [38]

As here it is given that

x = 150 m

a= 2 m/s^2

now initial speed of the plane must be zero as it start from rest

now we will use kinematics

$v_f^2 - v_i^2 = 2 a x$

$v_f^2 - 0 = 2(2)(150)$

$v_f =\sqrt{600} = 24.5 m/s$

so its final speed is maximum 24.5 m/s

so it will not reach to desired speed at the end of runway

5 0

2 years ago