Question

A chemist working as a safety inspector finds an unmarked bottle in a lab cabinet. A note on the door of the cabinet says the cabinet is used to store bottles of diethylamine, tetrahydrofuran, chloroform, ethanolamine, and acetone. First, from her collection of Material Safety Data Sheets (MSOS), the chemist finds the following information:
liquid density
diethylamine 1.1 gcm-3
tetrahydrofuran 0.7 9gcm-3
chloroform 0.71 gcm-3
ethanolamine 0.89 gcm-3
acetone 1.6 gcm-3
Next, the chemist measures the volume of the unknown liquid as 0.767 L and the mass of the unknown liquid as 682 g.
1. Calculate the density of the liquid.
2. Given the data above, is it possible to identify the liquid?
3. If it is possible to identify the liquid, do so.
a. dimethyl sulfoxide.
b. acetone.
c. diethylamine.
d. tetrahydrofuran .
e. carbon tetrachloride

Answer 1

Answer:

1. density = 0.89 g/cm3

2. Yes is possible to identify the liquid

3. ethanolamine

Explanation:

Data:

mass = 682 g

volume = 0.767 L = 767 mL or cm3

1.

To calculate the density of the liquid it is necessary to know that the density formula is:

$density=\frac{mass(g)}{volume(cm^{3}) }$

The data obtained is replaced in the formula:

$density=\frac{682g)}{767(cm^{3}) }=0.89\frac{g}{cm^{3} }$

2.

With the given data it is possible to identify the liquid, this because the density value is a basic property of each liquid.

3.

It is possible to determine what liquid it is, since when comparing the value obtained with those reported in the collection of Material Safety Data Sheets (MSOS), the value that agrees is that of ethanolamine.