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3 years ago

Where is Mars in the universe ?

Physics

1 answer:

ololo11 [35]3 years ago

5 0

RA 4h 21m 39s | Dec +22° 59′ 54″

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Water flows through a horizontal pipe (from a wider area to narrow area section) and then out into the atmosphere at a speed v1

Darina [25.2K]

Answer:

V = 6.36 m³

Explanation:

For this exercise we will use fluid mechanics relations, starting with the continuity equation.

Let's write the flow equation

Q = v₁ A₁

The area of a circle is

A = π r²

Radius is half the diameter

A = π/4 d²

Q = v₁ π/4 d₁²

Q = π/ 4 15 0.03 2

Q = 0.0106 m3 / s

The volume of water in t = 10 min = 10 60 = 600 s

Q = V / t

V = Q t

V = 0.0106 600

V = 6.36 m³

4 0

3 years ago

How many simple machines are in a wine opener? The kind with the bottle opener at the head and two "arms."

Blababa [14]

It uses the corkscrew to anchor it to the cork and a lever to pull the cork out

Hope this helps buddy:D

7 0

3 years ago

Read 2 more answers

An object is moving north with an initial velocity of 14 m/s accelerates 5m/s for 20 seconds. What is the final velocity of the

olga2289 [7]

Use the kinematic equation: Vf=Vi+at

Then plug;

Vi=14 m/s

a=5 m/s²

t=20 s. Therefore;

Vf=14+(5*20)

Vf=114 m/s.

6 0

4 years ago

A woman can row a boat at 4.0 mph is still water.

vovikov84 [41]

Answer:

1) $\theta=120^{\circ}$ from the positive x-axis.

2) $t=20\ min$

Explanation:

Given:

speed of rowing in still water, $v=4\ mph$

speed of water stream, $v_s=2\ mph$

we know that the direction of resultant of the two vectors is given by:

$tan\ \beta=\frac{v.sin\ \theta}{v_s+v.cos\ \theta}$

where:

$\beta=$ the angle of resultant vector from the positive x-axis.

$\theta =$ angle between the given vectors

When the rower wants to reach at the opposite end then:

$\beta =90^{\circ}$

so,

$tan\ 90^{\circ}=\frac{v.sin\ \theta}{v_s+v.cos\ \theta}$

$\Rightarrow v_s+v.cos\ \theta=0$

$2+4\times cos\ \theta=0$

$cos\ \theta=-\frac{1}{2}$

$\theta=120^{\circ}$ from the positive x-axis.

Now the resultant velocity of rowing in the stream:

$v_r=\sqrt{v^2+v_s^2+2\times v.v_s.cos\ \theta}$

$v_r=\sqrt{4^2+2^2+2\times 4\times 2\times cos\ 120}$

$v_r=12\ mph$

Therefore time taken to cross a 4 miles wide river:

$t=\frac{4}{12}$

$t=\frac{1}{3}\ hr$

$t=20\ min$

8 0

3 years ago

20 m

liubo4ka [24]

Answer:

1.9 km

Explanation:

The equation for vertical motion is ...

h(t) = -4.9t^2 +26t +20

This will have a zero near t = 5.988 seconds.*

The horizontal distance traveled in that time is ...

(310 m/s)(5.988 s) ≈ 1856 m ≈ 1.9 km

_____

* The root of a quadratic can be found numerous ways. We choose the quick and easy: let a graphing calculator show it to you.

5 0

4 years ago