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3 years ago

How many moles of butane do we have if we have 5.50 x 1024 molecules of butane (CH) ?

Chemistry

1 answer:

Dmitry [639]3 years ago

7 0

Answer:

9.14moles

Explanation:

Given parameters:

Number of atoms of butane = 5.5 x 10²⁴atoms

Unknown:

Number of moles = ?

Solution:

To solve this problem, we must understand that a mole of any substance contains the Avogadro's number of particles.

6.02 x 10²³ atoms makes up 1 mole of an atom

5.5 x 10²⁴ atoms will contain = $\frac{5.5 x 10^{24} }{6.02 x 10^{23} }$ = 9.14moles

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When water vapor condenses, how much heat energy will be released into the atmosphere?

Leona [35]

When water vapor condenses, 2260 joules/gram heat energy will be released into the atmosphere.

To add, heat energy (or thermal energy or simply heat) is defined as a form of energy which transfers among particles in a substance (or system) by means of kinetic energy of those particles. In other words, under kinetic theory, the heat is transferred by particles bouncing into each other.

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3 years ago

You are given a solution that is 518 mM lactose. You need to make up 4.5 L of 16.7 mM solution. What volume do you need to trans

OLga [1]

Answer:

The volume you need to transfer from the stock solution is 0.145 l

Explanation:

Since the number of moles of lactose in the volume of stock solution that you transfer will be the same as the number of moles of lactose in the final solution, you can use this expression:

number of moles in volume to transfer = number of moles in the final solution

Since number of moles = concentration * volume (if the concentration is expressed in molarity), then:

Ci * Vi = Cf * Vf

where:

Ci = concentration of the stock solution.

Vi = volume of the stock solution to be transferred.

Cf = concentration of the final solution

Vf = volume of the final solution

Then, replacing with the data:

518 mM * Vi = 16.7 mM * 4.5 l

Vi = 16.7 mM * 4.5 l / 518 mM

Vi = 0.145 l or 145 ml

Notice that any concentration unit can be used, as long as the units of the concentration of the stock and final solution are the same.

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3 years ago

A certain reaction with an activation energy of 205 kj/mol was run at 485 k and again at 505 k . what is the ratio of f at the h

lapo4ka [179]

Arrhenius' Law relates activation energy, Ea, rate constant, K, and temperature, T as per this equation:

K (T) = A * e ^ (-Ea / RT), where R is the universal constant of gases and A is a constant which accounts for collision frequency..

Then you can find the ration between K's at two different temperatures as:

K1 = A * e ^ (-Ea / RT1)

K2 = A* e ^(-Ea / RT2)

=> K1 / K2 = e ^ { (-Ea / RT1) - Ea / RT2) }

=> K1 / K2 = e ^ {(-Ea/ R ) *( 1 / T1 - 1 T2) }

=> K1 / K2 = e^ { (-205,000 j/mol / 8.314 j/mol*k )* ( 1 / 505K - 1/ 485K) }

=> K1 / K2 = e ^ (2.0134494) ≈ 7.5

Answer: 7.5

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3 years ago

Cuando viajo, me gusta comprar recuerdos.

kaheart [24]

Answer:

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Explanation:

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