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Katen [24]
3 years ago
7

20 POINTS WILL GIVE BRAINLY IF ANSWERED CORRECTLY

Chemistry
1 answer:
kolbaska11 [484]3 years ago
6 0

Answer:

D

Explanation:

The answer is D- There are more collisions of air molecules against the wall of the balloon.

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Be sure to answer these questions in your journal entry: • How long was the journey to Earth? • How fast did you travel? • Was y
damaskus [11]

Answer: What you doing

Explanation:

3 0
3 years ago
PLLLLLLLZ HELP IS NEEDED ASAP I WOULD REALLY APPRECIATE IT
Lesechka [4]

Answer:

1)Reactants

2)Light

3)An item that can increase reaction rates

4)Reactants must collide with each other

Less molecules lower the chance for collisions

The more collisions there are the higher the reaction rate

5 0
3 years ago
please hurry! If 3.87g of powdered aluminum oxide is placed in a container containing 5.67g of water, what is the limiting react
VikaD [51]

Answer:

Explanation:

Given parameters:

Mass of aluminium oxide = 3.87g

Mass of water = 5.67g

Unknown:

Limiting reactant = ?

Solution:

The limiting reactant is the reactant in short supply in a chemical reaction. We need to first write the chemical equation and convert the masses given to the number of moles.

Using the number of moles, we can ascertain the limiting reactants;

         Al₂O₃  + 3H₂O  →  2Al(OH)₃  

Number of moles;

            Number of moles = \frac{mass}{molar mass}

molar mass of Al₂O₃  = (2x27) + 3(16) = 102g/mole

    number of moles = \frac{3.87}{102}  = 0.04mole

   

molar mass of  H₂O = 2(1) + 16 = 18g/mole

    number of moles = \frac{5.67}{18}  = 0.32mole

From the reaction equation;

        1 mole of  Al₂O₃  reacted with 3 moles of H₂O

   0.04 mole of Al₂O₃ will react with 3 x 0.04 mole = 0.12 mole of H₂O

But we were given 0.32 mole of H₂O and this is in excess of amount required.

This shows that Al₂O₃ is the limiting reactant

           

6 0
3 years ago
Help ASAP!! Based on the chemical reaction shown, the reactants and products are best classified as
AleksAgata [21]

Answer:

the first one

Explanation:

as it contains in the product N so its the forst

3 0
3 years ago
If there are 50 grams of U-238 on day zero of radioactive decay, how much will there be after 4.5 billion years? A) 0.0 grams B)
Natalija [7]

Answer:

= 25 g

Explanation:

Using the formula;

A = A₀ (1/2)^(t/h)

where A is the final amount,

A₀ is the initial amount of the substance,

t is the time and

h is the half-life of the substance,

In this case; the half life of U-238 h is equal to 4.47 billion years.

A = A₀ (1/2)^(t/h)

A = 50 (1/2)^(4.5 / 4.47)

   = 24.88

  <u> = 25 g</u>

7 0
3 years ago
Read 2 more answers
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