Answer:
<h3>Step 1: </h3>
To relate the volume and molarity of a solution at two different concentrations, the expression used is :
M₁V₁ = M₂V₂
<h3>
step 2:</h3>
(2M) V₁ = (0.15M)(250ML)
V₁ = 18.75
step 3:
<h2>Pls, branliest! :)</h2>
Answer:
So ²³⁵UF₆ effuses 1.0043 times faster than ²³⁸UF₆
Explanation:
The rate of effusion of two gases A and B can be expressed by <em>Graham's law</em>:

Where M is the molar mass, and in this case A is ²³⁵UF₆ while B is ²³⁸UF₆.
So now we <u>calculate the molar mass of each mass</u>:
²³⁵UF₆ ⇒235 + 6*19 = 349 g/mol
²³⁸UF₆ ⇒238 + 6*19 = 352 g/mol
Putting the data in Graham's law:
= 1.0043
So ²³⁵UF₆ effuses 1.0043 times faster than ²³⁸UF₆.
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