Answer:
It can recognize several distinct flavor profiles: salty, sweet, sour, bitter, and umami — aka savory. Now, research suggests a sixth type of taste receptor on the tongue is responsible for people and animals being able to determine the taste of water among other fluids
Answer is: The zooplankton can be used to help control algal growth in some coral communities.
Hypothesis is a suggested explanation for an observable phenomenon.
Steps of the scientific method:
1) ask a question about something that is observed.
2) do background research.
3) construct a hypothesis, an attempt to answer questions with an explanation that can be tested. In this example, does the presence of a certain type of zooplankton inhibited the algae growth
4) test of hypothesis.
5) analyze collected data and draw a conclusion. In this example, the zooplankton can be used to help control algal growth.
Answer:
When in direct contact, the fast-moving molecules in the radiator collide with the slow-moving molecules in the ice cube. Kinetic energy is transferred from the molecules in the radiator to the molecules in the ice cube, causing a slowdown of the radiator molecules and an acceleration of the ice molecules.
Explanation:
Atoms has never been seen,nor experimentally detected. Their existence remained hypothetical.
Explanation:
The balanced equation of the reaction is given as;
Mg(OH)2 (s) + 2 HBr (aq) → MgBr2 (aq) + 2 H2O (l)
1. How many grams of MgBr2 will be produced from 18.3 grams of HBr?
From the reaction;
2 mol of HBr produces 1 mol of MgBr2
Converting to masses using;
Mass = Number of moles * Molar mass
Molar mass of HBr = 80.91 g/mol
Molar mass of MgBr2 = 184.113 g/mol
This means;
(2 * 80.91 = 161.82g) of HBr produces (1 * 184.113 = 184.113g) MgBr2
18.3g would produce x
161.82 = 184.113
18.3 = x
x = (184.113 * 18.3 ) / 161.82 = 20.8 g
2. How many moles of H2O will be produced from 18.3 grams of HBr?
Converting the mass to mol;
Number of moles = Mass / Molar mass = 18.3 / 80.91 = 0.226 mol
From the reaction;
2 mol of HBr produces 2 mol of H2O
0.226 mol would produce x
2 =2
0.226 = x
x = 0.226 * 2 / 2 = 0.226 mol
3. How many grams of Mg(OH)2 are needed to completely react with 18.3 grams of HBr?
From the reaction;
2 mol of HBr reacts with 1 mol of Mg(OH)2
18.3g of HBr = 0.226 mol
2 = 1
0.226 = x
x = 0.226 * 1 /2
x = 0.113 mol
