Answer:
Mass = 14.876 g
Explanation:
Given data:
Volume of gold = 0.77 cm³
Mass of gold = ?
Solution:
Density of gold from literature is 19.32 g/cm³
Formula:
d = m/v
d = density
m = mass
v = volume
by putting values,
19.32 g/cm³ = m/ 0.77 cm³
m = 19.32 g/cm³ × 0.77 cm³
m = 14.876 g
Answer:
480 L
Explanation:
In order to solve this question, you should be familiar with gas laws. (I will attach a picture showing all of them under my answer.) In this question in particular, however, we only need Charles's Law because we're dealing with temperature and volume.
As we can see, Charles's Law is:

or, initial volume over initial temperature equals final volume over final temperature.
In this question, 60 L is our <u>initial volume,</u> and 0.5 K is our <u>initial temperature</u> (K being Kelvin). We are only given 4 K as our <u>final temperature</u>. We are asked to solve for the <u>final volume</u>. Let's set up the equation and solve for
:
--------------------------------------------------------------------------------------------------------------
(60) / (0.5) =
/ (4)
↓
120 =
/ 4
×4 ×4
↓
= 480 L
--------------------------------------------------------------------------------------------------------------
There's our answer! Feel free to comment if you have any questions about my answer :)
Atoms are made up of protons , electrons and neutrons ..,, Atoms of the same element with different number of neutrons are called isotopes. Saying that substance “contains only one type of atom “ really means that it contains only atoms that all have the same number of protons .
Particles in a liquid move freely and liquids have a definite volume and indefinite shape since it occupies the shape of the container in which the liquid is in.
The balanced equation for the above reaction is;
4NH₃ + 7O₂ --> 4NO₂ + 6H₂O
stoichiometry of NH₃ to NO₂ is 4:4
the number of NH₃ moles consumed are - 4.0 g / 17 g/mol = 0.24 mol
number of NH₃ moles reacted are equivalent to number of NO₂ moles formed
therefore number of NO₂ moles formed - 0.24 mol x 46 g/mol = 11.04 g
mass of NO₂ formed is 11.04 g