Answer:
H₂(g) +I₂(g) ⟶ 2HI(g)
Explanation:
Kc =Kₚ when the number of moles of gaseous products equals the number of moles of gaseous reactants.
The HI reaction has two moles of gas on each side of the reaction arrow.
K = (Products)ⁿ/(Reactants)ⁿ = (Products/Reactants)ⁿ
Thus, if n is the same for products and reactants, you will get the same number whether you use concentrations or pressures, and Kc = Kₚ
Answer:
D) 1.61 times faster
Explanation:
= √(3)RTM
R constant= 0.08206
T=constant, so in this problem we dont need a value for it
M=17.031 g/mol
√(3)(0.08206)(17.031)= 2.047
= √(3)RTM
R constant= 0.08206
T=constant, so in this problem we dont need a value for it
M= 44.01 g/mol
√(3)(0.08206)(44.01)= 3.29
Since we are trying to measure how much faster NH3 will be, we have to realize that mass and speed have an inverse relationship.
So instead of doing (2.047)/(3.29) = 6.22
we have to flip the values to get (3.29)/(2.047)= 1.61
Answer:
A) secondary amide
Explanation:
When carboxylic acid reacts with a primary amine, a condensation reaction takes place with the elimination of a water molecule .
For example, ethanol reacts with methylamine which is a primary amine gives N-Methylacetamide and a water molecule as:

The bond formed which is
O
||
-- C ---NH ---
is known as secondary amide group as only one hydrogen is attached to nitrogen atom in the amide bond.
Answer:
0.375 moles of CaCO₃ are required
Explanation:
Given data:
Number of moles of sulfamic acid = 0.75 mol
Number of moles of calcium carbonate required = ?
Solution:
Chemical equation:
2H₃NSO₃ + CaCO₃ → Ca(SO₃NH₂)₂ + CO₂ + H₂O
Now we will compare the moles of H₃NSO₃ and CaCO₃ .
H₃NSO₃ : CaCO₃
2 : 1
0.75 : 1/2×0.75 = 0.375 mol
Thus, 0.375 moles of CaCO₃ are required.
The main factor is the size of the moon. which is small compared to the earth, meaning that the moon has less gravity, and more gas is allowed to escape the surface, Which basically means theres no atmosphere.