Answer 10
Explication nose
the mass of aluminum oxide (101.96 g/mol) produced from 1.74 g of manganese(iv) oxide (86.94 g/mol) is 1.36g
The reaction is 3 MnO2 + 4 Al ------ 2Al2o3+ Mn
3 mole of manganese oxide give 2 moles of aluminum oxide so by the reaction n( MnO2)/3 =n(al203)2
the formula is n= mass/M so, now substituting values
m (Al2O3)= m(MnO2) X 2 X M (Al2O3) / M(MnO2 X3
so, by substituting values, 2 X101.96 X1.74g / 3 X 86.94 =1.36g
so mass of aluminum oxide obtained = 1.36g
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Answer:
The answer is "
"
Explanation:
In the given question, the value of the 
and the 
is the rate value which is the constant that is 
. As per the temperature value when its increase rate is constantly increasing. 
is activation energy it is not dependent on the temperature that why the answer is .
Periodic table is arranged according to atomic size and other properties.
