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gregori [183]
3 years ago
12

Defined the work of vector​

Physics
1 answer:
cricket20 [7]3 years ago
7 0

Answer:

In physics, work is the amount of energy required to perform a given task (such as moving an object from one point to another). We start by defining the scalar product of two vectors, which is an integral part of the definition of work, and then turn to defining and using the concept of work to solve problems.

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Answer:

2.7km

Explanation:

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Then multiply time to get the distance of the car traveled.

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A playground merry-go-round has a radius of 4.6 m and a moment of inertia of 200 kg-m2 and turns with negligible friction about
tankabanditka [31]

Answer:

8050 J

Explanation:

Given:

r = 4.6 m

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F = 26.0 N

t = 15.0 s

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∑τ = Iα

Fr = Iα

α = Fr / I

α = (26.0 N) (4.6 m) / (200 kg m²)

α = 0.598 rad/s²

Now you can find the final angular velocity, then use that to find the rotational energy:

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ω = 8.97 rad/s

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W = ½ (200 kg m²) (8.97 rad/s)²

W = 8050 J

Or you can find the angular displacement and find the work done that way:

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θ = ½ (0.598 rad/s²) (15.0 s)²

θ = 67.3 rad

W = τθ

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6 0
3 years ago
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