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gregori [183]
3 years ago
12

Defined the work of vector​

Physics
1 answer:
cricket20 [7]3 years ago
7 0

Answer:

In physics, work is the amount of energy required to perform a given task (such as moving an object from one point to another). We start by defining the scalar product of two vectors, which is an integral part of the definition of work, and then turn to defining and using the concept of work to solve problems.

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A tank is filled with an ideal gas at 400 K and pressure of 1.00 atm.
bekas [8.4K]

To find the temperature it is necessary to use the expression and concepts related to the ideal gas law.

Mathematically it can be defined as

PV=nRT

Where

P = Pressure

V = Volume

n = Number of moles

R = Gas constant

T = Temperature

When the number of moles and volume is constant then the expression can be written as

\frac{P_1}{T_1}=\frac{P_2}{T_2}

Or in practical terms for this exercise depending on the final temperature:

T_2 = \frac{P_2T_1}{P_1}

Our values are given as

T_1 = 400K\\P_1 = 1atm\\P_2 = 2atm

Replacing

T_2 = \frac{(2)(400)}{1}\\T_2 = 800K

Therefore the final temperature of the gas is 800K

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3 years ago
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iogann1982 [59]
The correct answer is:
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6 0
3 years ago
A pipe of length 10.0 m increases in length by 1.5 cm when its temperature is increased by 90°F. What is its coefficient of line
azamat

The coefficient of linear expansion, given that the length of the pipe increased by 1.5 cm is 1.67×10¯⁵ /°F

<h3>How to determine the coefficient of linear expansion</h3>

From the question given above, the following data were obtained

  • Original diameter (L₁) = 10 m
  • Change in length (∆L) = 1.5 cm = 1.5 / 100 = 0.015 m
  • Change in temperature (∆T) = 90 °F
  • Coefficient of linear expansion (α) =?

The coefficient of linear expansion can be obtained as illustrated below:

α = ∆L / L₁∆T

α = 0.015 / (10 × 90)

α = 0.015 / 900

α = 1.67×10¯⁵ /°F

Thus, we can conclude that the coefficient of linear expansion is 1.67×10¯⁵ /°F

Learn more about coefficient of linear expansion:

brainly.com/question/28293570

#SPJ1

3 0
1 year ago
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