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2 years ago

Defined the work of vector

Physics

1 answer:

cricket20 [7]2 years ago

7 0

Answer:

In physics, work is the amount of energy required to perform a given task (such as moving an object from one point to another). We start by defining the scalar product of two vectors, which is an integral part of the definition of work, and then turn to defining and using the concept of work to solve problems.

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A student is playing with a pendulum. He gives the ball a push and watches the ball as it swings. After a while, the ball stops

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A because it’s not good

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3 years ago

Which one of the following is an example of an indicator?

a_sh-v [17]

B. litmus paper :) :)

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3 years ago

A sound wave is determined to have a frequency of 1,000 Hz and a wavelength of 35 cm. What is the speed of this wave? If the sou

mars1129 [50]

Answer:

350 m/s

31°C

Explanation:

Speed of sound is given as the product of frequency and wavelength

S=fw

Where s represent the speed in m/s, f is frequency and w is wavelength

Conversion

Taking 1m to be 100 cm then 35 cm will be 35/100=0.35m

Substituting 0.35 m for w and 1000 Hz for f then

S=1000*0.35=350 m/s

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3 years ago

An LC circuit consists of a 3.14 mH inductor and a 5.08 µF capacitor. (a) Find its impedance at 55.7 Hz. 563.57 Correct: Your an

ANEK [815]

Answer:

$z=561.7$

$z=214.1$

Explanation:

L = inductance of the Inductor = 3.14 mH = 0.00314 H

C = capacitance of the capacitor = 5.08 x 10⁻⁶ F

f = frequency = 55.7 Hz

Impedance is given as

$z=\frac{1}{2\pi fC} - 2\pi fL$

$z=\frac{1}{2(3.14) (55.7)(5.08\times 10^{-6})} - 2(3.14) (55.7)(0.00314)$

$z=561.7$

f = frequency = 11000 Hz

Impedance is given as

$z= - \frac{1}{2\pi fC} + 2\pi fL$

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$z=214.1$

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3 years ago

A man wears convex lens glasses of focal length 30cm in order to correct his eyes defect. Instead of the optimum 25cm, his dista

omeli [17]

Answer:

14 cm

Explanation:

F = (frac{uv}{u – v})

F = +ve

v = -ve

30 = (frac {25 {times} (-v)}{25 – (-v)})

v = (frac {25 {times} (-v)}{25+v})

v = 14cm

(Note that either negative or positive values go to show the positioning and hence, they are not a strong necessity in your final answer.)

So happy that i could help you!

Now this question could turn out to be easy for you!!

7 0

1 year ago

Defined the work of vector​

Defined the work of vector