Distance = speed / time
speed = 95 m/s
time = 3 s
distance = 95 / 3 m
displacement = 95/3 m or 32 m (2 s.f.)
Answer:
<h2>Rotational inertia first decreases and then increases as the satellite is ready to land</h2>
Explanation:
This problem is based on the conservation of angular momentum.
<h2>What is the Law of Conservation of Angular Momentum
?</h2>
The Law of Conservation of Angular Momentum states that
<em>"The angular momentum of a system of particles around a point in a fixed inertial reference frame is conserved if there is no net external torque around that point".</em>
The rate of rotation increases greatly when the Satelite is moved inwards by 10%, decreasing the moment of inertia. The work-done to pull in the Satelite results in an increase in rotational kinetic energy.
Answer:
-4.8 m/s²
Explanation:
Apply Newton's second law:
∑F = ma
F − mg = ma
300 N − (60 kg) (9.8 m/s) = (60 kg) a
a = -4.8 m/s²
The acceleration five seconds after jumping is 4.8 m/s² downward.
The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.