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2 years ago

What is the relation between force and acceleration

1 answer:

6 0

The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.

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Who has the best answer for this

ioda

Answer:

electricity because it has more percentage nd energy

Explanation:

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1 year ago

A 2000 Kg car going 20 m/s crashes into a wall. What is the force of the car on the wall?

lidiya [134]

Answer:

40,000N

Explanation:

Force = Acceleration × Mass

2000×20=40,000

4 0

3 years ago

You are determining the mass of an object using a triple beam balance. When the pointer is lined up with the zero mark, the ride

astra-53 [7]

We add the values on each of the riders:
300 + 20 + 8
= 328 grams

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3 years ago

Read 2 more answers

The Canadian bobsled team hit the brakes on the sled they are traveling East in so that it decelerates at a rate of 0.43

mafiozo [28]

Answer:

Explanation:

85 = ½(0.43)t²

t = √(2(85)/0.43)

t = 19.883380...

t = 20 s

v→ 8.55 m/s initial, 0 m/s final

a← 0.43 m/s²

8 0

2 years ago

A centrifuge has an angular velocity of 3,000 rpm, what is the acceleration (in unit of the earth gravity) at a point with a rad

Anna71 [15]

Answer:

$a_{r} = 1006.382g \,\frac{m}{s^{2}}$

Explanation:

Let suppose that centrifuge is rotating at constant angular speed, which means that resultant acceleration is equal to radial acceleration at given radius, whose formula is:

$a_{r} = \omega^{2}\cdot R$

Where:

$\omega$ - Angular speed, measured in radians per second.

$R$ - Radius of rotation, measured in meters.

The angular speed is first determined:

$\omega = \frac{\pi}{30}\cdot \dot n$

Where $\dot n$ is the angular speed, measured in revolutions per minute.

If $\dot n = 3000\,rpm$ , the angular speed measured in radians per second is:

$\omega = \frac{\pi}{30}\cdot (3000\,rpm)$

$\omega \approx 314.159\,\frac{rad}{s}$

Now, if $\omega = 314.159\,\frac{rad}{s}$ and $R = 0.1\,m$ , the resultant acceleration is then:

$a_{r} = \left(314.159\,\frac{rad}{s} \right)^{2}\cdot (0.1\,m)$

$a_{r} = 9869.588\,\frac{m}{s^{2}}$

If gravitational acceleration is equal to 9.807 meters per square second, then the radial acceleration is equivalent to 1006.382 times the gravitational acceleration. That is:

$a_{r} = 1006.382g \,\frac{m}{s^{2}}$

6 0

2 years ago

What is the relation between force and acceleration​

What is the relation between force and acceleration