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kotegsom [21]
3 years ago
14

Which is an example of a chemical change

Chemistry
2 answers:
kondaur [170]3 years ago
7 0

Answer: C) baking a cake

Explanation: I said that because A & B are examples of physical change and D & E makes no sense to me. You could’ve just searched it too but it’s C ✨

jonny [76]3 years ago
4 0
The answer is baking a cake.
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5) answer is A
Burka [1]

Answer:

A)  positive; added

Explanation:

Based on the reaction:

2NaHCO3(s) + 129kJ → Na2CO3(s) + H2(g) + CO2(g)

<em>2 moles of NaHCO3 requires 129kJ to produce 1 mole of Na2CO3, 1 mole of H2 and 1 mole of CO2.</em>

<em />

That means, the energy must be added being, thus, an exothermic reaction. The exothermic reactions have ΔH >0.

Thus, right answer is:

A)  positive; added

3 0
3 years ago
What is the total energy change for the following reaction:CO+H2O-CO2+H2
Alekssandra [29.7K]

Answer:

\large \boxed{\text{-41.2 kJ/mol}}

Explanation:

Balanced equation:    CO(g) + H₂O(g) ⟶ CO₂(g) + H₂(g)

We can calculate the enthalpy change of a reaction by using the enthalpies of formation of reactants and products

\Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)

(a) Enthalpies of formation of reactants and products

\begin{array}{cc}\textbf{Substance} & \textbf{$\Delta_{\text{f}}$H/(kJ/mol}) \\\text{CO(g)} & -110.5 \\\text{H$_{2}$O} & -241.8\\\text{CO$_{2}$(g)} & -393.5 \\\text{H$_{2}$(g)} & 0 \\\end{array}

(b) Total enthalpies of reactants and products

\begin{array}{ccr}\textbf{Substance} & \textbf{Contribution)/(kJ/mol})&\textbf{Sum} \\\text{CO(g)} & -110.5& -110.5 \\\text{H$_{2}$O(g)} &-241.8& -241.8\\\textbf{Total}&\textbf{for reactants} &\mathbf{ -352.3}\\&&\\\text{CO}_{2}(g) & -393.5&-393.5 \\\text{H}_{2} & 0 & 0\\\textbf{Total}&\textbf{for products} & \mathbf{-393.5}\end{array}

(c) Enthalpy of reaction \Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)= \text{-393.5 kJ/mol - (-352.3 kJ/mol}\\= \text{-393.5 kJ/mol + 352.3 kJ/mol} = \textbf{-41.2 kJ/mol}\\ \text{The total enthalpy change is $\large \boxed{\textbf{-41.2 kJ/mol}}$}

4 0
3 years ago
El método de cristalización sirve para separar agua salada y obtener ambos componentes por separado
GaryK [48]

Answer:

Si.

Explicación:

Sí, el método de cristalización se utiliza para separar la sal del agua y obtener los componentes de la sal y del agua por separado. La cristalización es un método o técnica que se utiliza para purificar compuestos sólidos. Este proceso funciona mejor debido a las diferentes solubilidades del compuesto deseado y las impurezas que están presentes en un solvente dado. El proceso de cristalización implica enfriar agua salada para formar cristales de hielo puro. Luego, los cristales de hielo se separan de la salmuera no congelada, se lavan para eliminar la sal residual y luego se derrite la solución para producir agua dulce.

5 0
3 years ago
What is biodiversity? <br> Answers for the question is in the picture! NO LINKS OR FILES!
vivado [14]

Answer: a

Explanation:

6 0
3 years ago
Read 2 more answers
35 points for one question
True [87]

The result of the procedure is that the copper strip should go through oxidation.

<h3>How to explain the procedure?</h3>

The copper strip should be considered as the anode and the nail should be considered as the cathode.

The anode is the electrode of an electrochemical cell at which oxidation occurs. The anode should be + while the cathode should be negative. Both should be placed in the tank that should be filled with the electrolyte solution.

Learn more about oxidation on:

brainly.com/question/25886015

#SPJ1

4 0
2 years ago
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