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rjkz [21]
3 years ago
11

How can Cold air be made to rise

Chemistry
1 answer:
Anastaziya [24]3 years ago
5 0
Turn it into warm air
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A wafer of gold measuring 15 cm x 20 cm has a mass of 600 g. How thick is this wafer in mm ?
Gre4nikov [31]
600,000 mm if im not mistaken.
7 0
3 years ago
How many moles of water will be produced if the reaction begins with 9.50 mol NH3?
gogolik [260]
It would cost a little less than one thing but it was a little bit too late to get it to me
8 0
3 years ago
Compute the atomic density (the number of atoms per cm3 ... rather than the mass density g/cm3) for a perfect crystal of silicon
serious [3.7K]

Answer:

        \large\boxed{\large\boxed{5.00\times 10^{22}atoms/cm^3}}

Explanation:

You can convert the <em>density</em> into <em>atomic density</em> using the <em>atomic weight </em>and Avogadro's number

A dimensional analysis is very helpful:

           \dfrac{g}{cm^3}\times \dfrac{mol}{g}\times \dfrac{atoms}{mol}=\dfrac{atoms}{cm^3}

Follow the chain: g cancels with g, mol cancels with mol; at the end, what remains is atoms/cm³, which is what you want.

Use that with your data:

         \dfrac{2.33g}{cm^3}\times \dfrac{1mol}{28.09g}\times \dfrac{6.022\times 10^{23}atoms}{mol}=\approx 5.00\times10^{22}atoms/cm^3

3 0
3 years ago
The solubility of the ionic compound MX3, having a molar mass of 288 g/mol, is 3.60 x 10-2 g/L. Calculate the KSP of the compoun
GarryVolchara [31]

K_{sp} of the compound is found to be  5.04 ×10^{-10}.

Solubility :Solubility can be define as the amount of a substance that dissolves or mixes in a given amount of solvent at specific conditions.

Solubility equilibrium

Ksp = [A^{+} ]^{a} [B^{-} ]^{b}

Ksp = solubility product constant

A+ = cation in an aquious solution

B- = anion in an aqueous solution

a, b = relative concentrations of a and b

Given,

Solubility = s = 3.60 × 10^{-2} g/L

molar mass = 288 g/ mol

∴ s= 3.60 × 10^{-2} g/L ÷ 288 g/ mol = 1.25 ×10^{-4} mol/ L

Reaction:

MX3 ⇄ M + 3X

           s       3s

K_{sp} =[ M^{+3}] [ X^{-1}]^{3} = solubility product

∴ K_{sp} =[s]^{} [3s]^{3}

∴ K_{sp} = 3 s^{4}

∴ K_{sp} = 3 × (3.60 × 10^{-2} )^{4}

∴ K_{sp} = 503.8848 ×10^{-8}  = 5.04 ×10^{-10}

Learn more about solubility here .....

brainly.com/question/23946616

#SPJ1

7 0
2 years ago
What is the conjugate base of ch3ch2co2h?
Novay_Z [31]
The conjugate base of ch3ch2co2h or propanoic acid would be CH3CH2COO- or propanoate. The conjugate base is what is left after an acid has donated a proton in a reaction. Hope this answers the question. Have a nice day.
3 0
3 years ago
Read 2 more answers
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