Answer:
450.0 L.
Explanation:
- We can use the general law of ideal gas: <em>PV = nRT.</em>
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and T are constant, and have different values of P and V:
<em>(P₁V₁) = (P₂V₂).</em>
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V₁ = 760.0 L, P₁ = 450.0 mm Hg,
V₂ = ??? L, P₂ = 760.0 mm Hg (standard pressure = 1.0 atm = 760 mm Hg).
∴ V₂ = (P₁V₁)/(P₂) = (760.0 L)(450.0 mm Hg)/(760.0 mm Hg) = 450.0 L.
I think it’s D but don’t come at me if it’s wrong
Answer:
A and B
Explanation:
This is because there was emission of gamma (Y) radiations in both the reactions.
Answer:
1/16 is the answer.........
<span>SO3
for the formal charges, we have:
for the single-bonded oxygens F.C. = 6 - [1/2(2) + 6] = -1
for the double-bonded oxygen F.C. = 6 - [1/2(4) + 4] = 0
for the sulfur F.C. = 6 - [1/2(8) + 0] = 2
Again, the formal charges add to zero. The oxidation numbers of O and S are -2 and +6, respectively. Note the three resonance forms!</span>
