The expression of the magnetic force and solving the determinant allows to shorten the result for the value of the magnetic force are:
- In Cartesian form F = 2.46 i ^ - 0.605 j ^
- In the form of magnitude and direction F = 2.53 N and θ = 346.2º
Given parameters.
- Length of the wire on the z axis is: L = 25.0 cm = 0.25 m.
- The current i = 9.00 A in the positive direction of the z axis.
- The magnetic field B = (-0.242 i ^ - 0.985 j ^ -0.336 k ^ ) T
To find.
The magnetic force on a wire carrying a current is the vector product of the direction of the current and the magnetic field.
F = i L x B
Where the bold letters indicate vectors, F is the force, i the current, L a vector pointing in the direction of the current and B the magnetic field.
The best way to find the force is to solve the determinant, in general, a vector (L) is written in the form of the module times a <em>unit vector</em>.
Let's calculate.
F = 2.5 (0.985 i ^ - 0.242 j ^)
F = ( 2.46 i ^ - 0.605 j^ ) N
To find the magnitude we use the Pythagorean theorem.
F =
F =
F = 2.53 N
Let's use trigonometry for the direction.
Tan θ ’=
θ'= tan⁻¹
θ'= tan⁻¹1 (
)
θ’= -13.8º
To measure this angle from the positive side of the x-axis counterclockwise.
θ = 360- θ'
θ = 360 - 13.8
θ = 346.2º
In conclusion using the expression of the magnetic force and solving the determinant we can shorten the result for the value of the force are:
- In Cartesian form F = 2.46 i ^ - 0.605 j ^
- In the form of magnitude and direction F = 2.53 N and θ = 346.2º
Learn more here: brainly.com/question/2630590
Answer:
v = ω R
number of seconds in 24 hrs = 24 * 3600 = 86400 s / da = T (period)
f = 1 / T
ω = 2 Π f = 2 Π / T = 2 Π / 86400
v = 2 Π / 8.64E4 * 6.0E6 = 436 m / s
Check:
S = 2 Π * 6.0E6 = 3.77E7 m/da
S / T = 3.77E7 m/da / 8.64E4 s/da = 436 m / s
Lets use Dimensional analysis.

<h3>LHS:-</h3>
![\\ \sf\longmapsto s=\left[M^0LT^0\right]](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20s%3D%5Cleft%5BM%5E0LT%5E0%5Cright%5D)
<h3>RHS</h3>

![\\ \sf\longmapsto \left[M^0LT^{-1}\right]\left[M^0L^0T^1\right]+\dfrac{1}{2}\left[M^0LT^{-2}\right]\left[M^0L^0T^1\right]^2](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cleft%5BM%5E0LT%5E%7B-1%7D%5Cright%5D%5Cleft%5BM%5E0L%5E0T%5E1%5Cright%5D%2B%5Cdfrac%7B1%7D%7B2%7D%5Cleft%5BM%5E0LT%5E%7B-2%7D%5Cright%5D%5Cleft%5BM%5E0L%5E0T%5E1%5Cright%5D%5E2)
![\\ \sf\longmapsto L+\dfrac{1}{2}\left[LT^{-2}\right]\left[T^2\right]](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20L%2B%5Cdfrac%7B1%7D%7B2%7D%5Cleft%5BLT%5E%7B-2%7D%5Cright%5D%5Cleft%5BT%5E2%5Cright%5D)


![\\ \sf\longmapsto [L^1]](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5BL%5E1%5D)
![\\ \sf\longmapsto \left[M^0LT^0\right]](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cleft%5BM%5E0LT%5E0%5Cright%5D)
LHS=RHS
Hence verified
Explanation:
In induction, what charge does a neutral substance gain compared to the object brought near it?
The neutral object gains the same type of charge as the object that touched it because the electrons move from one object to the other (Figure 10.16). Induction is the movement of electrons within a substance caused by a nearby charged object, without direct contact between the substance and the object.
Answer:
g ≈ 7.4 m/s²
Explanation:
The acceleration due to gravity on planet XX is ...
g = GM/r² = (6.67·10^-11 × 4·10^22)/(6·10^5)^2
g ≈ 7.4 m/s²