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beks73 [17]
3 years ago
13

If you adjusted the frequency to be lower than the resonant frequency, would the current amplitude have been less than, equal to

, or greater than the current amplitude you found at resonance? Explain.
Physics
1 answer:
balandron [24]3 years ago
3 0

Answer:

Current amplitude will be less than the current amplitude at resonance.

Explanation:

Resonance in series RLC circuit, is a condition where the capacitive and inductive reactances are equal, thus making the circuit purely resistive due to which the overall impedance of the circuit at resonace is minimum resulting in the maximum amplitude of current as there is inverse relationship between impedance and current.

When the frequency is less than resonance frequency, the circuit will be capacitive in nature (since, capacitive reactance is inversely proportional to the frequency wheras inductive reactance is directly proportional to it) and the overall impedance of the circuit is more than that at resonance hence the current in the circuit will also be less than that at resonance.

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With what speed does the can move immediately after the collision? Answer in units of m/s.
Ratling [72]

Answer:

1.74 m/s

Explanation:

From the question, we are given that the mass of the an object, m1= 2.7 kilogram(kg) and the mass of the can,m(can) is 0.72 Kilogram (kg). The velocity of the mass of an object(m1) , V1 is 1.1 metre per seconds(m/s) and the velocity of the mass of can[m(can)], V(can) is unknown- this is what we are to find.

Therefore, using the formula below, we can calculate the speed of the can, V(can);

===> Mass of object,m1 × velocity of object, V1 = mass of the can[m(can)] × velocity is of the can[V(can)].----------------------------------------------------(1).

Since the question says the collision was elastic, we use the formula below

Slotting in the given values into the equation (1) above, we have;

1/2×M1×V^2(initial velocity of the first object) + 1/2 ×M(can)×V^2(final velocy of the first object)= 1/2 × M1 × V^2 m( initial velocity of the first object).

Therefore, final velocity of the can= 2M1V1/M1+M2.

==> 2×2.7×1.1/ 2.7 + 0.72.

The velocity of the can after collision = 1.74 m/s

7 0
3 years ago
When 30 V is applied across a resistor it generates 600 W of heat: what is the magnitude of its resistance?
grandymaker [24]

Answer:

<h2>1.5 ohms</h2>

Explanation:

Power is expressed as P = V²/R

R = resistance

V = supplied voltage

Given P = 600W and V = 30V

R = V²/P

R = 30²/600

R = 900/600

R = 1.5ohms

magnitude of its resistance is 1.5ohms

3 0
3 years ago
a waterwheel built in Hamah, Syria, has a radius of 20 m . If the tangential velocity at the wheels edge is 7.85 m/s , what is t
gtnhenbr [62]

Answer:

3.08m/s²

Explanation:

Given parameters:

Radius = 20m

Tangential velocity  = 7.85m/s

Unknown:

Centripetal acceleration  = ?

Solution:

Centripetal acceleration is the acceleration of a body along a circular path.

 it is mathematically given as;

       a  = \frac{v^{2} }{r}  

v is the tangential velocity

r is the radius

      a  = \frac{7.85^{2} }{20}   = 3.08m/s²

4 0
3 years ago
A rocket initially at rest accelerates at a rate of 99.0 meters/second2. Calculate the distance covered by the rocket if it atta
Jobisdone [24]

Answer: The correct answer is option b.

Explanation: We are given that the rocket is at rest initially final velocity is 445m/s.

The acceleration of the rocket is 99.0m/s^2

To calculate the distance of rocket, we use third equation of motion, which is:

v^2-u^2=2as

where, v = final velocity = 445m/s

u = initial velocity = 0m/s

a = acceleration = 99m/s^2

s = distance = ? m

Putting values in above equation, we get:

(445)^2-(0)^2=2(99)s\\\\s=1\times 10^3meters

3 0
3 years ago
In what way does the sun's rays of light hit the earth?<br><br> PLease anSWER
Dafna11 [192]

Answer:

The Sun's energy gets to the Earth through radiation, which you can prove just by standing outside and letting the sun's rays warm your face on a sunny day. Every object around you is continually radiating unless its temperature is at absolute zero, at which point its molecules completely stop moving.

Hope that helps :)

3 0
3 years ago
Read 2 more answers
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