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Goryan [66]
3 years ago
6

What is the slope of the line that passes through the points (2,-3) and (-2,5)

Mathematics
1 answer:
Likurg_2 [28]3 years ago
8 0

Answer:

-2

Step-by-step explanation:

m = 5-(-3) / -2-2

m = 5+3/-4

m = 8/-4

m = 2/-1

m = -2

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Let ABC be an isosceles triangle with AB = AC and ∠BAC=30°. Side AB and the median AD contain points Q and P respectively (point
Svet_ta [14]

Answer:

  15°

Step-by-step explanation:

Since P is on the median of ΔABC, it is equidistant from points B and C as well as from C and Q. Thus, points B, C, and Q all lie on a circle centered at P. (See the attached diagram.)

The base angles (B and C) of triangle ABC are (180° -30°)/2 = 75°. This means arc QC of the circle centered at P has measure 150°. The diameter of circle P that includes point Q is defined to intersect circle P at R.

Central angle RPC is the difference between arcs QR and QC, so is 180° -150° = 30°. Inscribed angle RQC has half that measure, so is 15°.  Angle PQC has the same measure as angle RQC, so is 15°.

Angle PQC is 15°.

5 0
4 years ago
A rectangle has an area of 19.38 cm2. When both the length and width of the rectangle are increased by 1.50 cm, the area of the
Lostsunrise [7]

Answer: 5.7\ cm

Step-by-step explanation:

Given

Rectangle has an area of 19.38\ cm^2

Suppose rectangle length and width are l and w

If each side is increased by 1.50\ cm

Area becomes A_2=35.28\ cm^2

We can write

\Rightarrow lw=19.38\quad \ldots(i)\\\\\Rightarrow (l+1.5)(w+1.5)=35.28\\\Rightarrow lw+1.5(l+w)+1.5^2=35.28\\\text{use (i) for}\ lw\\\Rightarrow 19.38+1.5(l+w)=35.28-2.25\\\Rightarrow l+w=9.1\quad \ldots(ii)

Substitute the value of width from (ii) in equation (i)

\Rightarrow l(9.1-l)=19.38\\\Rightarrow l^2-9.1l+19.38=0\\\\\Rightarrow l=\dfrac{9.1\pm\sqrt{(-9.1)^2-4(1)(19.38)}}{2\times 1}\\\\\Rightarrow l=\dfrac{9.1\pm\sqrt{5.29}}{2}\\\\\Rightarrow l=\dfrac{9.1\pm2.3}{2}\\\\\Rightarrow l=3.4,\ 5.7

Width corresponding to these lengths

w=5.7,\ 3.4

Therfore, we can write the length of the longer side is 5.7\ cm

8 0
3 years ago
Segment AB has endpoints A(–4, 6) and B(1, 4). After a dilation, centered at the origin, the image of A is (–6, 9). Without meas
Ksivusya [100]
With A and its image one can get the dilation factor;
That is dilation scale factor = -6/-4 or 9/6 = 3/2
Therefore, to get the image of B we multiply the coordinates of B by the dilation factor; 
(1,4) 3/2 = (1.5, 6)
Thus the image of B = (1.5,6)
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Which is greater? -(-3) or -(3) ? need asap!
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