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Ac method
for y=ax^2+bx+c
the ac method is normally used for when a≠1
it is used as an aid to help factor
so
0=1x^2-8x+15
multiply a and c (1 times 15=15)
what 2 numbers mulitply to get 15 and add to get -8?
-3 and -5
split the middle up to that
0=1x^2-3x-5x+15
group
0=(x^2-3x)+(-5x+15)
undistribute
0=x(x-3)-5(x-3)
undistribute (x-3)
0=(x-5)(x-3)
set to zero
x-5=0
x=5
x-3=0
x=3
solutions are x= 3 and 5
Answer:
I think it is 22
Step-by-step explanation:
60-12= 48-18= 30-8= 22
Answer:
Solve for y 3/7=15. 37y=15 3 7 y = 15. Multiply both sides of the equation by 73 7 3. 73.37 y=73.15 7 3. 3 7 y = 7 3. 15
Step-by-step explanation:
Solve for y by simplifying both sides of the equation, then isolating the variable. Y=35
Let's say that:
y=(2n-8)
y+8=2n
(y+8)/2=n
then switch the variables
(n+8)/2