Answer:
i d k wears the circle at? ill update my answer when u put up the circle
Step-by-step explanation:
Answer:
5 , 10 , 15 , 20 , 25 , 30 , 35 , 40 , 45 , 50 , 55 , 60
6, 12, 18 , 24 , 30, 36 , 42 , 48, 54, 60
30 and 60
Yes, if you solve the problem in the parenthesis, then you add the two solutions together and you got ur final solution
AC = (-5)(-3)
sum = -8
x^2 - 5x - 3x + 15
x(x-5)-3(x-5)
(x-3) (x-5)
x=3 x=5
Do you want a general solution or from 0 <= x < 2pi?
tan^2(2x) - 1 = 0
tan^2(2x) = 1
Take the square root of both sides,
tan(2x) = +/- 1
Two equations:
tan(2x) = 1
tan(2x) = -1
Solve each equation.
tan(2x) = 1, 2x = {pi/4, 5pi/4, 9pi/4, 13pi/4},
x = { pi/8, 5pi/8, 9pi/8, 13pi/8 }
tan(2x) = -1, 2x = { 3pi/4, 7pi/4, 11pi/4, 15pi/4 },
x = { 3pi/8, 7pi/8, 11pi/8, 15pi/8}
So for solutions within [0, 2pi),
x = {pi/8, 3pi/8, 5pi/8, 7pi/8, 9pi/8, 11pi/8, 13pi/8, 15pi/8 }