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3 years ago

12

What is the composition of sucrose?

1 answer:

Lina20 [59]3 years ago

6 0

Answer:

Sucrose is made up of one glucose and one fructose molecule, and are joined together by a glycosidic bond

Explanation:

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4vir4ik [10]

What does botanist study?

$\implies {\blue {\boxed {\boxed {\purple {\sf {D.\: Plants}}}}}}$

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4 years ago

12. Label Each part of the atom:

enot [183]

Answer:

Atom Labeling

Explanation:

Y- neutron

Z-protron

X - electron

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3 years ago

Consider the reaction below.

anygoal [31]

Answer:

B.

Explanation:

Oxidation - losing electrons. It is Zn, and it is losing 2 electrons.

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4 years ago

Return the first n>0 elements of list l. assume the list elements are numbered from 1 to n

Daniel [21]

I dont get it someone please help

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3 years ago

A 47.1 g sample of a metal is heated to 99.0°C and then placed in a calorimeter containing 120.0 g of water (c = 4.18 J/g°C) at

wlad13 [49]

Answer : The metal used was iron (the specific heat capacity is $0.44J/g^oC$ ).

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$C_1$ = specific heat of metal = ?

$C_1$ = specific heat of water = $4.18J/g^oC$

$m_1$ = mass of metal = 47.1 g

$m_2$ = mass of water = 120 g

$T_f$ = final temperature of water = $24.5^oC$

$T_1$ = initial temperature of metal = $99^oC$

$T_2$ = initial temperature of water = $21.4^oC$

Now put all the given values in the above formula, we get

$47.1g\times c_1\times (24.5-99)^oC=-120g\times 4.18J/g^oC\times (24.5-21.4)^oC$

$c_1=0.44J/g^oC$

Form the value of specific heat of metal, we conclude that the metal used in this was iron.

Therefore, the metal used was iron (the specific heat capacity is $0.44J/g^oC$ ).

3 0

3 years ago