natural resources: materials or substances such as minerals, forests, water, and fertile land that occur in nature and can be used for economic gain.

renewable resources: a natural resource that is unlimited or that is naturally replenished rather quickly, such as sunlight or water

non renewable resources: (also called a finite resource) is a natural resource that cannot be readily replaced by natural means at a pace quick enough to keep up with consumption.

8 0

2 years ago

Do you expect a strong chemical bond to have a higher or lower frequency than a weak bond?

Llana [10]

Answer:

Higher frequency

Explanation:

We can imagine a chemical bond between two atoms as if it were two balls connected by a spring.

According to Hooke's Law, the stretching frequency f is

$f = \dfrac{1}{2 \pi}\sqrt{ \dfrac {k}{\mu}}$

where µ is the reduced mass of the system

$\mu = \dfrac{m_{1} + m_{2}}{m_{1}m_{2} }$

The strength of the bond is analogous to k, the force constant of the spring. Then,

$f \propto \sqrt{k}$

Thus, the stronger the bond, the greater the frequency of vibration.

6 0

3 years ago

What makes up a film badge?

Inessa [10]

Film badges is a personal dosimeter used for monitoring cumulative radiation dose due to ionizing radiation.

A panel or layers of photographic film covered with black paper and exposed to air ,salt,and other chemicals on clear acetate

8 0

2 years ago

Read 2 more answers

How much heat is required to heat 1.6g of ice from -16c to steam at 112c?

oksian1 [2.3K]

Answer:

Total heat ≅ 49.07 kJ

Explanation:

Given that:

mass = 1.6 g = 0.016 kg

Initial temperature = - 16 ° C

final temperature = 112° C

specific heat for ice = 2.06 kJ/kgC

specific heat of water = 4.186 kJ/kgC

heat fusion of ice = 334 kJ/kg

specific heat for steam = 2.1 kJ/kgK

heat of vaporization of water = 2256 kJ/kg

To heat ice from -16 ° C to 0 ° C

Q₁ = 2.06 kJ/kgC × 0.016 kg × 16 ° C

Q₁ = 0.52736 kJ

To melt Ice at 0° C

Q₂= 334 kJ/kg × 0.016 kg = 5.344 kJ

To heat water from 0° C to 100° C

Q₃ = 4.186 kJ/kgC × 0.016 kg × 100° C

Q₃ = 6.6976 kJ

To vaporize water to steam at 100° C

Q₄ = 2256 kJ/kg × 0.016 kg = 36.096 kJ

To heat steam from 100C to 112° C

Q₅ = 2.1 kJ/kgC × 0.016 kg × 12 C

Q₅ = 0.4032 kJ

Total heat = Q₁ + Q₂ + Q₃ + Q₄ + Q₅

Total heat = (0.52736 + 5.344 + 6.6976 + 36.096 + 0.4032) kJ

Total heat = 49.06816 kJ

Total heat ≅ 49.07 kJ

6 0

3 years ago