Answer:
The molarity of the sulfuric acid is 0.018 M
Explanation:
The molarity of a solution is the number of moles of the solute (sulfuric acid in this case) in a 1-liter solution.
Every 100 g of the solution, we have 95 g sulfuric acid because its concentration is 95% w/w.
With the density, we can calculate how many liters are 100 g of solution:
density = mass / volume
1.85 g / ml = 100 g / volume
volume = 100 g / 1.85 g/ml
volume = 54.1 ml or 0.0541 l
Now, we know that we have 95 g sulfuric acid in 0.0541 l solution. In 1 l, we have then:
1 l * 95g / 0.0541 l = 1.756 g sulfuric acid.
But we want to know how many moles sulfuric acid we have per liter. Then, using the molar mass, we can calculate how many moles there are in 1.756 g sulfuric acid:
1.756 g * 1 mol / 98.08 g = 0.018 mol
The molarity is 0.018 M
Bulk property are those properties that does not depend on the amount of substance.
<h3>What is a bulk property?</h3>
The term bulk property can also be referred to as the intensive properties of a substance. These are those properties that does not depend on the amount of substance. This means that they are characteristic of the material.
The percent by mass refers to the percentage of an atom that is present in a compound. If we must be able to calculate the percentage by mass then we must know the mass of the sample and the masses of the elements found in the sample.
Learn more about bulk properties:brainly.com/question/25960022
#SPJ1
First we must write a balanced chemical equation for this reaction
The mole ratio for the reaction between 
and 
is 1:2. This means 1 moles of will neutralize 2 moles . Now we find the moles of each reactant based on the mass and molar mass.
The was enough to neutralize the acid because 18.87:39.67 is the same as 1:2 mol ratio.
Moles = (6.74*10^23)/(6.02*10^23) =1.119 moles
1.119*44.09=49.36g
I would say A but I am not sure
