Answer:
a) T = 608.22 N
b) T = 608.22 N
c) T = 682.62 N
d) T = 533.82 N
Explanation:
Given that the mass of gymnast is m = 62.0 kg
Acceleration due to gravity is g = 9.81 m/s²
Thus; The weight of the gymnast is acting downwards and tension in the string acting upwards.
So;
To calculate the tension T in the rope if the gymnast hangs motionless on the rope; we have;
T = mg
= (62.0 kg)(9.81 m/s²)
= 608.22 N
When the gymnast climbs the rope at a constant rate tension in the string is
= (62.0 kg)(9.81 m/s²)
= 608.22 N
When the gymnast climbs up the rope with an upward acceleration of magnitude
a = 1.2 m/s²
the tension in the string is T - mg = ma (Since acceleration a is upwards)
T = ma + mg
= m (a + g )
= (62.0 kg)(9.81 m/s² + 1.2 m/s²)
= (62.0 kg) (11.01 m/s²)
= 682.62 N
When the gymnast climbs up the rope with an downward acceleration of magnitude
a = 1.2 m/s² the tension in the string is mg - T = ma (Since acceleration a is downwards)
T = mg - ma
= m (g - a )
= (62.0 kg)(9.81 m/s² - 1.2 m/s²)
= (62.0 kg)(8.61 m/s²)
= 533.82 N
direction ................................................................
I believe it is kinetic energy
Answer:
d
Explanation:
First law of thermodynamics
It is also known as energy conservation law.It state that net work in a cyclic process is equal to net heat in that cycle.
From first law
Q=ΔU + W
ΔU = Q - W
ΔU is the change in internal energy of gas.
Q is heat transfer from the system or to the system.
W is the work done by the system or on the system.
If work done on the system then it will be taken as positive and If work done by the system then it will be taken as negative.
If heat taken by system it will taken as positive and If heat rejected by system it will taken as negative.
So Q will be positive if system gains heat and work will be positive if work is done on the system.
Answer:
Mechanical energy into electrical energy
Explanation:
