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pickupchik [31]
3 years ago
6

Can there be any heat transfer between two bodies that are at the same temperature but at different pressures?

Physics
1 answer:
Alenkinab [10]3 years ago
3 0

Answer:

No

Explanation:

When the two bodies at different temperatures then heat transfer takes place between two bodies. Temperature is the necessary condition for the heat transfer.

The energy can flow due to pressure difference but the heat transfer can not take place only due to pressure difference. Heat transfer needs temperature difference.

Therefore the answer will be No.

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svlad2 [7]
The answer for your problem is shown on the picture.

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2 years ago
How does a toaster oven use micro waves
vekshin1
It uses microwaves as little heatwaves and uses them to heat the food
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3 years ago
We now have an algebraic expression with only one variable, which can be solved. Once we have that, we can plug it back into one
Len [333]

Answer:

A=1

B=-2

Explanation:

Part A and B of the question wasn't given, however, I attached the relevant parts to solve this question as follows.

From part B as attached, it shows that the right option is C which is

2A+3B=-4

Substituting B with 3A-5 then we form the second equation as shown

2A+3(3A-5)=-4

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2A+9A-15=-4

Re-arranging, then

11A=-4+15

Finally

11A=11

A=1

To obtain B, we already know that 3A-5 so substituting the value of A into the above then we obtain

B=3(1)-5=-2

Therefore, required values are 1 and -2

3 0
3 years ago
A boat moves through the water of a river at 10m/s relative to the water, regardless of the boat ‘s direction . If the water in
katen-ka-za [31]

Answer:

The appropriate solution is "61.37 s".

Explanation:

The given values are:

Boat moves,

= 10 m/s

Water flowing,

= 1.50 m/s

Displacement,

d = 300 m

Now,

The boat is travelling,

= 10+1.50

= 11.5 \ m/s

Travelling such distance for 300 m will be:

⇒ v = \frac{d}{t} \ sot \ t

      =\frac{d}{v}

On putting the values, we get

      =\frac{300}{11.5}

      =26.08 \ s

Throughout the opposite direction, when the boat seems to be travelling then,

= 10-1.50

= 8.5 \ m/s

Travelling such distance for 300 m will be:

⇒ v=\frac{v}{t} \ sot \ t

      =\frac{d}{v}

On putting the values, we get

      =\frac{300}{8.5}

      =35.29 \ s

hence,

The time taken by the boat will be:

= 26.08+35.29

= 61.37 \ s

8 0
2 years ago
PLz I Need Help PLZZZ ASAP
AURORKA [14]

#1

As we are increasing the frequency in the simulation the wavelength is decreasing

So if speed remains constant then wavelength and frequency depends inversely on each other

If we are in boat and and moving over very small wavelengths then these small wavelength will be encountered continuously by the boat in short interval of times

#2

As we are changing the amplitude in the simulation there is no change in the speed frequency and wavelength.

So amplitude is independent of all these parameter

Amplitude of wave will decide the energy of wave

So light of greater intensity is the light of larger amplitude

#3

In our daily life we deal with two waves

1 sound waves

2 light waves

3 0
2 years ago
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