<span>The number of cell phone minutes used by high school seniors follows a normal distribution with a mean of 500 and a standard deviation of 50. what is the probability that a student uses more than 580 minutes?
Given
μ=500
σ=50
X=580
P(x<X)=Z((580-500)/50)=Z(1.6)=0.9452
=>
P(x>X)=1-P(x<X)=1-0.9452=0.0548=5.48%
</span>
For this case, the first thing to do is to observe that the figure is symmetrical with respect to the FH axis.
Therefore, the following lengths are the same:
So, by equalizing both sides we have:
From here, we clear the value of m.
We have then:
Answer:
The value of m is given by:
They will need 3 cars, but one of the cars will be having 3 passengers instead of 4. :)
Answer:
(x) = 
x + 8
Step-by-step explanation:
let y = f(x) and rearrange making x the subject, that is
y = 9(x - 8) ← divide both sides by 9
= x - 8 ( add 8 to both sides )
+ 8 = x
Change y back into terms of x with x = (x) , thus
(x) = x + 8
Answer:
14 items
Step-by-step explanation:
20 seconds minus the six it takes to process purchase is 14 and if i takes 1 second to scan each item 14 times 1 is 14
