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3 years ago

Hardest question that nobody can answer about diffusion

Chemistry

1 answer:

valkas [14]3 years ago

7 0

Is the movement of a substance from an area of high concentration to an area of low concentration

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A student went outside every night for eight nights to look at the Moon. The pictures below show how the Moon looked each

Temka [501]

Answer:

mother chod fgjgcbu to ghbj

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3 years ago

Calculate the net change in enthalpy for the formation of one mole of nitric acid from nitrogen, hydrogen and oxygen from these

deff fn [24]

The formation of nitric acid from nitrogen, hydrogen, and oxygen can be written as,

N₂ + H₂ + 3O₂ --> 2HNO₃

The net enthalpy of formation of nitric acid is calculated by,
Hrxn = Hproduct - Hreactant

Since all the reactants are in their elemental forms, the simplified equation would be,

Hrxn = Hproduct

Substituting,

Hrxn = (-186.81 kJ/mol)(2 mols)

<em>Answer: -372.42 kJ</em>

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3 years ago

If you take a part time job while you are still in school what might your opportunity scost be

yarga [219]

The opportunity costs of working part-time while attending high school could be studying time, grades, and your own free time. It depends on the person, how they do in school, but if it were for me, I would say the benefits outweigh the costs. I have enough time to study and still get good grades in school.

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2 years ago

Read 2 more answers

Phosgene (COCl2) is a toxic substance that forms readily from carbon monoxide and chlorine at elevated temperatures: CO(g) + Cl2

lapo4ka [179]

Answer: Concentration of $CO$ = 0.328 M

Concentration of $Cl_2$ = 0.328 M

Concentration of $COCl_2$ = 0.532 M

Explanation:

Moles of $CO$ and $Cl_2$ = 0.430 mole

Volume of solution = 0.500 L

Initial concentration of $CO$ and $Cl_2$ = $\frac{moles}{volume}=\frac{0.430}{0.500}=0.860M$

The given balanced equilibrium reaction is,

$CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)$

Initial conc. 0.860M 0.860M 0

At eqm. conc. (0.860-x) M (0.860-x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[COCl_2]}{[CO][Cl_2]}$

Now put all the given values in this expression, we get :

$4.95=\frac{x}{(0.860-x)^2}$

By solving the term 'x', we get :

x = 0.532 M

Thus, the concentrations of $CO,Cl_2\text{ and }COCl_2$ at equilibrium are :

Concentration of $CO$ = (0.860-x) M =(0.860-0.532) M = 0.328 M

Concentration of $Cl_2$ = (0.860-x) M = (0.860-0.532) M = 0.328 M

Concentration of $COCl_2$ = x M = 0.532 M

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3 years ago

Condensation is the change from liquid to water cycle

kogti [31]

Answer:

hi! merry xmas!

Explanation:

Condensation is the process where water vapor becomes liquid. It is the reverse of evaporation, where liquid water becomes a vapor.

Condensation happens one of two ways: Either the air is cooled to its dew point or it becomes so saturated with water vapor that it cannot hold any more water.

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3 years ago

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Hardest question that nobody can answer about diffusion​

Hardest question that nobody can answer about diffusion