Suppose the spring begins in a compressed state, so that the block speeds up from rest to 2.6 m/s as it passes through the equilibrium point, and so that when it first comes to a stop, the spring is stretched 0.20 m.
There are two forces performing work on the block: the restoring force of the spring and kinetic friction.
By the work-energy theorem, the total work done on the block between the equilbrium point and the 0.20 m mark is equal to the block's change in kinetic energy:

or

where <em>K</em> is the block's kinetic energy at the equilibrium point,

Both the work done by the spring and by friction are negative because these forces point in the direction opposite the block's displacement. The work done by the spring on the block as it reaches the 0.20 m mark is

Compute the work performed by friction:

By Newton's second law, the net vertical force on the block is
∑ <em>F</em> = <em>n</em> - <em>mg</em> = 0 ==> <em>n</em> = <em>mg</em>
where <em>n</em> is the magnitude of the normal force from the surface pushing up on the block. Then if <em>f</em> is the magnitude of kinetic friction, we have <em>f</em> = <em>µmg</em>, where <em>µ</em> is the coefficient of kinetic friction.
So we have



Answer:
Explanation:
The value of acceleration due to gravity of mars is same as that the value of acceleration due to gravity of Mercury.
The value of acceleration due to gravity of a planet depends on its mass and the radius.
The formula for the acceleration due to gravity is given by

Where, M be the mass of the planet, R be the radius of the planet.
As according to the question, the value of acceleration due to gravity for Mercury is same as that of Mars.


As teh radius of Mercury is small, and acceleration due to gravity is same, it is possible because the mass of Mercury is more than the mass of Mars.
Answer:
15448
Explanation:
Compounded Quarterly:
A=P\left(1+\frac{r}{n}\right)^{nt}
A=P(1+
n
r
)
nt
Compound interest formula
P=11000\hspace{35px}r=0.057\hspace{35px}t=6\hspace{35px}n=4
P=11000r=0.057t=6n=4
Given values
A=11000\left(1+\frac{0.057}{4}\right)^{4(6)}
A=11000(1+
4
0.057
)
4(6)
Plug in values
A=11000(1.01425)^{24}
A=11000(1.01425)
24
Simplify
A=15448.0290759
A=15448.0290759
Use calculator
Kinetic Energy,K.E=1/2MV²
mass,m=16kg
velocity,v=4m/s
K.E=1/2×16×4²
=128kgm²/s²
=128 Joules
Answer:0.25 kg-m/s
Explanation:
Given
mass of blob 
initial velocity 
time of collision 
we know Impulse is equal to change in momentum
initial momentum 

Final momentum 
as final velocity is zero
Impulse 

