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attashe74 [19]
3 years ago
13

When the balloon sticks to the wall (assuming it sticks to the wall). It is

Physics
1 answer:
inn [45]3 years ago
8 0
The answer is false
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Which of these experiments would make use of quantitative data?
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An experiment that would make use of quantitative data would be A. A study of the different amounts of time it takes water to evaporate completely.
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You leave a pastry in the refrigerator on a plate and ask your roommate to take it out before youget home so you can eat it at r
Sidana [21]

Answer:

   c_{e1} =  \frac{(m_2 c_{e2} \ + m_3 c_{e3} ) \  (T_{Teq} - T_2)     }{m_1 (T_1 - T_{eq}) }

Explanation:

This is a calorimeter problem where the heat released by the console is equal to the heat absorbed by the cupcake and the plate.

           Q_c = Q_{abs}

where the heat is given by the expression

           Q = m c_e ΔT

            m₁ c_{e1) (T₁-T_{eq}) = m₂ c_{e2} (T_{eq} -T₂) + m₃ c_{e3} (T_{eq}- T₁)

note that the temperature variations have been placed so that they have been positive

They ask us for the specific heat of the console

           c_{e1} =  \frac{(m_2 c_{e2} \ + m_3 c_{e3} ) \  (T_{Teq} - T_2)     }{m_1 (T_1 - T_{eq}) }

3 0
3 years ago
a plane being propelled due east is actually moving at 225mph an angle of 40 degrees north of east, how fast is the crosswind th
Marianna [84]

Answer:

144.63 mph

Explanation:

225 sin (40)

4 0
3 years ago
SOMEONE PLEASE HELP ME ASAP PLEASE!!!!​
Anarel [89]

Answer:

B. m^2

Explanation:

The unit would be m^2 because there are two m's so the result is m^2.

m*m= m^2

If there were 3 m's the result wouldve been m^3 and so on...

6 0
3 years ago
The magnetic field at the center of a wire loop of radius , which carries current , is 1 mT in the direction (arrows along the w
Citrus2011 [14]

Complete Question

 The complete question is shown on the first uploaded image

Answer:

The magnetic field is B_{net} = \frac{1}{4}  * mT

And the direction is  -\r k

Explanation:

      From the question we are told that

                 The magnetic field at the center is B = 1mT

Generally magnetic field is mathematically represented as

              B = \frac{\mu_o I}{2R}

We are told that it is equal to 1mT

So

                B = \frac{\mu_o I}{2R} = 1mT

From the first diagram we see that the effect of the current flowing in the circular loop is  (i.e the magnetic field generated)

                         \frac{\mu_o I}{2R} = 1mT

 This implies that the effect of a current flowing in the smaller semi-circular loop is (i.e the magnetic field generated)

                   B_1 = \frac{1}{2} \frac{\mu_o I}{2R}

and  for the larger semi-circular loop  is

                 B_2 = \frac{1}{2} \frac{\mu_o I}{2 * (2R)}

Now a closer look at the second diagram will show us that the current in the semi-circular loop are moving in the opposite direction

    So the net magnetic field would be

                   B_{net} = B_1 - B_2

                        =  \frac{1}{2} \frac{\mu_o I}{2R} -\frac{1}{2} \frac{\mu_o I}{2 * (2R)}

                        =\frac{\mu_o I}{4R} -\frac{\mu_o I }{8R}

                        =\frac{\mu_o I}{8R}

                        = \frac{1}{4} \frac{\mu_o I}{2R}

Recall  \frac{\mu_o I}{2R} = 1mT

    So  

             B_{net} = \frac{1}{4}  * mT

Using the Right-hand rule we see that the direction is into the page which is -k

3 0
3 years ago
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