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JulsSmile [24]
3 years ago
12

a ball is thrown down at 25 m/s from a 500m tall building. how fast is it traveling when it hits the ground?

Physics
1 answer:
Mrrafil [7]3 years ago
3 0

Answer:

The speed of the ball when it hits the ground is 102.1 m/s

Explanation:

Given;

initial velocity of ball, u = 25 m/s

distance traveled by the ball = height of the building = h = 500 m

when the ball hits the ground, the final velocity, v = ?

The final velocity of the ball is given by;

v² = u² + 2gh

where;

g is acceleration due to gravity = 9.8 m/s²

v² = (25)² + 2(9.8)(500)

v² = 10425

v = √10425

v = 102.1 m/s

Therefore, the speed of the ball when it hits the ground is 102.1 m/s

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For the PE formula, why is the height required for calculations? Why do we need to know the height in order to determine PE? *
Fudgin [204]

Answer:

Answer in Explanation

Explanation:

Whenever we talk about the gravitational potential energy, it means the energy stored in a body due to its position in the gravitational field. Now, we know that in the gravitational field the work is only done when the body moves vertically. If the body moves horizontally on the same surface in the Earth's Gravitational Field, then the work done on the body is considered to be zero. Hence, the work done or the energy stored in the object while in the gravitational field is only possible if it moves vertically. This vertical distance is referred to as height. <u>This is the main reason why we require height in the P.E formula and calculations.</u>

The derivation of this formula is as follows:

Work = Force * Displacement

For gravitational potential energy:

Work = P.E

Force = Weight = mg

Displacement = Vertical Displacement = Height = h

Therefore,

P.E = mgh

5 0
3 years ago
Tech A says that the maintenance requirements of a vehicle have not changed since the creation of the automobile. Tech B says th
pogonyaev

Answer:

Tech B

Explanation:

There is a revolution of changes occur since the beginning of vehicle creation. Many technology came into existence and proposed us the best design, features and model. But as a machine, several fatigue or wear and tear can happen to this hence a proper maintenance is required in order for smooth running of your vehicle.

Many manufacturers have booklet that mention the proper maintenance interval for better running of your vehicle. As daily environment is changing, the  maintenance requirements of a vehicle is also changing. New technology is bringing new features hence their maintenance  rate as well as requirement also needs to be upgraded.

5 0
4 years ago
A child drops a ball. The ball hits the ground and bounces. The graph to the left shows the velocity-time graph for the ball fro
WINSTONCH [101]

Answer:

Consider the velocity-time graph attached below.

The velocity-time graph represents the acceleration of a body under a force.

We can see that is the graph that if a child release the ball above the ground at A, it hits the ground at B. Bounces back with a reaches the top again at C, and hits the ground again at D.

The slope of velocity time graph represents acceleration. From A to B, velocity in increasing constantly with respect to time, which means constant acceleration from A to B. AS velocity increase, momentum of the ball also increases, which results in the increase of Kinetic energy.

At B, the ball hits the ground, the velocity decreases, momentum decrease s, because kinetic energy is transferred from the ball to the ground, due to which the ball would not attain the same height after the bounce.

Then the velocity remains negative at C, which means that now the ball is moving in opposite direction till C. It reaches its new at height at C, which is not the same as that of A because of lost in Kinetic Energy, and fall again.

4 0
3 years ago
A 5.30 m long pole is balanced vertically on its tip. What will be the speed (in meters/second) of the tip of the pole just befo
suter [353]

Answer:

v = 17.66 m/s

Explanation:

As we know that the lower end of the pole is fixed in the ground and it start rotating about that end

so here we can say that the gravitational potential energy of the pole will convert into rotational kinetic energy of the pole about its one end

so we have

mgL = \frac{1}{2}(\frac{mL^2}{3})\omega^2

so we have

\omega = \sqrt{\frac{6g}{L}}

now we have

\omega = \sqrt{\frac{6(9.81)}{5.30}}

\omega = 3.33 rad/s

now the speed of the other tip of the pole is given as

v = \omega L

v = (3.33)(5.30) = 17.66 m/s

8 0
4 years ago
Plz answer the question
Vikentia [17]

Answer:

Ray A = Incidence ray

Ray B = Reflected ray

Explanation:

From the law of reflection,

Normal: This is the line that makes an angle of 90° with the reflecting surface.

Ray A is the incidence ray: This is the ray that srikes the surface of a reflecting surface. The angle formed between the normal and the incidence ray is called the incidence angle

Ray B is the reflected ray: This is the ray leaves the surface of a reflecting surface. The angle formed between the reflected ray and the normal is called reflected angle

3 0
3 years ago
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