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nataly862011 [7]
3 years ago
11

If you ran 15 km/h for 20 min, how much distance would you cover?

Physics
1 answer:
nikitadnepr [17]3 years ago
4 0
Since we have 15 kilometers per hour, and we're looking for 20 minutes, let's set up proportions.
20/60 minutes = x/15
20/60 = 1/3, so let's leave that simplified.
1/3 = x/15
Look at the denominators, 3 to 15 is a factor of 5, so multiply the numerator by 5.
1 • 5 = 5, so you will cover 5 kilometers in 20 minutes.

I hope this helps!
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3 years ago
How do I do trebuchet calculations????? Help me please
Mnenie [13.5K]
I found some good web pages with highly detailed answers to predicting the range of a trebuchet. A very simple model we have used in my Intro to Eng class just uses the mass of the projectile (m2), the mass of the counter weight (m1), and the height the counter weight falls (h): Range (max) = 2 * (m1/m2) * h Now the efficiency of the trebuchet will cause this model to be off by quite a bit. But once you have a working trebuchet, we find this model works well when we vary m1, m2, or h. We assume we have a take off angle of 45 degrees above the horizon. This solution is based on the classic max range ballistics problem - 45 degree take off angle. It also assumes converting all the potential energy of the counter weight to kinetic energy of the projectile. That is why the efficiency issue comes up as a lot of energy is lost due to friction in the moving trebuchet. If the projectile spins a lot then it will travel a shorter distance as the potential energy is split into kinetic and rotational energy. Projectile shape and wind will also vary the results. Good luck.
5 0
3 years ago
A football player runs at 8m/s and plows into a 80kg referee standing on the field causing the referee to fly forward at 5m/s. I
madreJ [45]

The topic here is momentum.

When a collision is said to be elastic, it means that the colliding objects now travel at their own new, indivual and distinct velocities, often in different directions.

So we write that as,

(mass of football player x velocity of football player) + (mass of referee x velocity of referee) = (mass of football player x velocity of football player) + (mass of referee x velocity of referee)

(M × 8) + (80 × 0) = (M× 0) + (80 × 5)

8M = 400

M = 50 kg

4 0
3 years ago
5) An object 9.0 m off the ground has 86 J of
MissTica

Answer:

Correct answer: Ep₁ = 105.11 J

Explanation:

if we take as the zero reference point the bottom of the hole then the height difference is 11 m. Let named h₁ = 11 m

The formula for calculating potential energy is:

E p = m g h  => mg · 9.0 m = 86 J  => mg = 86/9

when we substitute this into the next formula we get

m g h₁ = 86/9 · 11 = 105.11 J

God is with you!!!

6 0
3 years ago
A 50 kg athlete running at speed v grabs a light rope that hangs from a 10-meter-high platform and swings to a maximum of 1.8 m
balu736 [363]
The answer is: 1.8 meters.

Explanation:
An athlete swinging can be considered a pendulum.

The pendulum's maximum height is the point at which it changes direction, which means that its velocity is equal to zero. In this point, for the mechanical energy conservation, all its kinetic energy is transformed into potential energy. Similarly, when the pendulum is at its resting position (when the athlete grabs the rope), its energy is totally kinetic.

Therefore we can say that:
\frac{1}{2}m v_{1} ^{2}  = mgh_{max}

Solving for h:
h_{max} =  \frac{v^{2}}{g}

As we can see, the maximum height is independent on the mass and on the length of the rope, therefore it will be the same for the 100kg-athlete as it is for the 50kg-athlete, since their initial speeds are the same.

We know that the <span>50kg-athlete reached a height of 1.8 m, h</span>ence, the maximum height reached by the 100kg-athlete will be 1.8 m.
4 0
4 years ago
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