Answer:
efficiency =42.62%
AMOUNT OF POWER REJECTED IS 20.080 kW
Explanation:
given data:
power 20 hp
heat energy = 35kW
power production = 20 hp = 20* 746 W = 14920 Watt [1 hp =746 watt]
=42.62%
b) 
= 20.080 kW
AMOUNT OF POWER REJECTED IS 20.080 kW
Answer:
Explanation:
The "Move Over law" varies by state, but generally requires you vacate the adjacent lane (the one you're currently traveling in), or slow down. Some states have specific speed requirements; others require only "safe and prudent" speed.
The sort of parked vehicles that require you to "move over" also vary by state. It would be "safe and prudent" to move over for <em>any</em> vehicle parked on the shoulder, especially if there are people or animals around those vehicles.
Answer:
Ammonia gas a hazardous gas to our health, when we are exposed to it for a long time. The gas is lighter than air, that means it's high concentration may not be noticed at the point of leakage, because it flows with the wind direction. Ammonia gas detector are used to determine the concentration of the gas at a particular place. We can use the dispersion modelling software program to know the exact position, where we can place the gas detector, which would be where evacuation is needed.
During evacuation, when the concentration of the gas has increased, a self-contained breathing apparatus should be used for breathing, and an encapsulated suit should be worn to prevent ammonia from reacting with our sweat or any other chemical burn. A mechanic ventilation will also be needed in the place of evacuation, so that the ammonia concentration in that area can be dispersed.
is the volume of the sample when the water content is 10%.
<u>Explanation:</u>
Given Data:
First has a natural water content of 25% = 
= 0.25
Shrinkage limit, 
We need to determine the volume of the sample when the water content is 10% (0.10). As we know,
![V \propto[1+e]](https://tex.z-dn.net/?f=V%20%5Cpropto%5B1%2Be%5D)
------> eq 1
The above equation is at 
,
Applying the given values, we get
Shrinkage limit is lowest water content
Applying the given values, we get
Applying the found values in eq 1, we get
