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ankoles [38]
3 years ago
8

At the end of a power distribution system, a certain feeder supplies three distribution transformer, each one supplying a group

of customers whose connected loads are as under: Transformer Load Demand factor Diversity factor Transformer No. 1 10kW 0.65 1.5 Transformer No. 2 12kW 0.6 3.5 Transformer No. 3 15kW 0.7 1.5 If the diversity factor among the transformer is 1.3; find the maximum load on the feeder.
Engineering
1 answer:
murzikaleks [220]3 years ago
6 0

Answer:

≈ 18.62 kw

Explanation:

Given data :

Diversity factor among transformer = 1.3

No of transformers       load      demand factor   diversity factor

Transformer 1               10 kw      0.65                    1.5

Transformer 2              12 kw      0.6                       3.5

Transformer 3               15 kw      0.7                      1.5

calculate the maximum load on the feeder

demand factor = max demand /  load

Max demand = demand factor * load

max demands:

Transformer 1 = 0.65 * 10 = 6.5

Transformer 2 = 0.6 * 12 = 7.2

Transformer 3 = 0.7 * 15 = 10.5

Diversity factor = ( summation of max demands ) / maximum load on feeder

  1.3 = ( 6.5 +7.2 + 10.5 ) / max load on feeder

hence : max load on feeder = 24.2 / 1.3 = 18.62 kw

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A 5-in.-diameter pipe is supported every 9 ft by a small frame consisting of two members asshown. Knowing that the combined weig
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Answer:

AC: at D , M_max = 12.25 lb-ft

BC: at E , M_max = 8.75 lb-ft

Explanation:

Given:

- The diameter of the pipe d = 5-in

- The pipe is supported every L = 9 ft of pipe in length

- The weight if the pipe + contents W = 10 lb/ft

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determine the magnitude and location of the maximum bending moment in members AC and BC.

Solution:

- The figure (missing) is given in the attachment.

- We will first determine the external forces acting on each member:

             Section: 9-ft section of pipe.

                     Sum of forces perpendicular to member AC = 0

                     F_d - 0.8*W*L = 0

                     F_d = 0.8*10*9 = 72 lb

                     Sum of forces perpendicular to member BC = 0

                     F_e - 0.6*W*L = 0

                     F_e = 0.6*10*9 = 54 lb

              F_d = 72 lb ,  F_e = 54 lb

- Then we will determine the support reactions for each member AC point A and BC point B.

              Section: Entire Frame.

                    Sum of moments about point B = 0

                    -A_y*(18.75/12) + F_d*(d /2*12) + F_e*((11.25-2.5)/12) = 0

                    -A_y*(1.5625) + 15 + 39.375 = 0

                    A_y = 34.8 lb  

                   Sum of forces in vertical direction = 0

                     A_y + B_y - 0.8*F_d - 0.6*F_e = 0

                     B_y = 0.8*(72) + 0.6*(54) - 34.8

                     B_y = 55.2 lb  

                   Sum of forces in horizontal direction = 0

                     A_x + B_x - 0.6*F_d + 0.8*F_e = 0

                     A_x + B_x = 0

               Section: Member AC

                    Sum of moments about point C = 0

                     F_d*(2.5/12) - A_y*(12/12) - A_x*(9/12) = 0

                     72*2.5 - 34.8*12 - 9*A_x = 0

                     A_x = -237.6 / 9 = - 26.4 lb

                     B_x = - A_x = 26.4 lb

                     A_x = -26.4 lb  ,  B_x = 26.4 lb

- Now we will calculate bending moment for each member at different sections.

               Member AC:

                    From point A till just before point D

                     -0.6*A_x*x - A_y*0.8*x + M = 0

                     15.84*x - 27.84*x + M = 0

                      M = 12*x   ..... max value at D, x = 12.25 in

                      M_max = 12*12.25/12 = 12.25 lb-ft

               Member BC:

                    From point B till just before point E

                     -0.8*B_x*x + B_y*0.6*x + M = 0

                     -21.12*x + 33.12*x + M = 0

                      M = -12*x   ..... max value at E, x = 11.25 - 2.5 = 8.75 in

                      M_max = -12*8.75/12 = -8.75 lb-ft

- The maximum bending moments and their locations are:

                      AC: at D , M_max = 12.25 lb-ft

                      BC: at E , M_max = 8.75 lb-ft

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3 years ago
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