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ankoles [38]
3 years ago
8

At the end of a power distribution system, a certain feeder supplies three distribution transformer, each one supplying a group

of customers whose connected loads are as under: Transformer Load Demand factor Diversity factor Transformer No. 1 10kW 0.65 1.5 Transformer No. 2 12kW 0.6 3.5 Transformer No. 3 15kW 0.7 1.5 If the diversity factor among the transformer is 1.3; find the maximum load on the feeder.
Engineering
1 answer:
murzikaleks [220]3 years ago
6 0

Answer:

≈ 18.62 kw

Explanation:

Given data :

Diversity factor among transformer = 1.3

No of transformers       load      demand factor   diversity factor

Transformer 1               10 kw      0.65                    1.5

Transformer 2              12 kw      0.6                       3.5

Transformer 3               15 kw      0.7                      1.5

calculate the maximum load on the feeder

demand factor = max demand /  load

Max demand = demand factor * load

max demands:

Transformer 1 = 0.65 * 10 = 6.5

Transformer 2 = 0.6 * 12 = 7.2

Transformer 3 = 0.7 * 15 = 10.5

Diversity factor = ( summation of max demands ) / maximum load on feeder

  1.3 = ( 6.5 +7.2 + 10.5 ) / max load on feeder

hence : max load on feeder = 24.2 / 1.3 = 18.62 kw

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A sign erected on uneven ground is guyed by cables EF and EG. If the force exerted by cable EF at E is 46 lb, determine the mome
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M_AD = 1359.17 lb-in

Explanation:

Given:

- T_ef = 46 lb

Find:

- Moment of that force T_ef about the line joining points A and D.

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- Find the position of point E:

                           mag(BC) = sqrt ( 48^2 + 36^2) = 60 in

                           BE / BC = 45 / 60 = 0.75

Hence,                E = < 0.75*48 , 96 , 36*0.75> = < 36 , 96 , 27 > in

- Find unit vector EF:

                           mag(EF) = sqrt ( (21-36)^2 + (96+14)^2 + (57-27)^2 ) = 115 in

                           vec(EF) = < -15 , -110 , 30 >

                           unit(EF) = (1/115) * < -15 , -110 , 30 >

- Tension            T_EF = (46/115) * < -15 , -110 , 30 > = < -6 , -44 , 12 > lb

- Find unit vector AD:

                           mag(AD) = sqrt ( (48)^2 + (-12)^2 + (36)^2 ) = 12*sqrt(26) in

                           vec(AD) = < 48 , -12 , 36 >

                           unit(AD) = (1/12*sqrt(26)) * < 48 , -12 , 36 >

                           unit (AD) = <0.7845 , -0.19612 , 0.58835 >

Next:

                           M_AD = unit(AD) . ( E x T_EF)

                           M_d = \left[\begin{array}{ccc}0.7845&-0.19612&0.58835\\36&96&27\\-6&-44&12\end{array}\right]

                            M_AD = 1835.73 + 116.49528 - 593.0568

                            M_AD = 1359.17 lb-in

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