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Advocard [28]
3 years ago
14

Pls help me on this it’s past due ty

Chemistry
1 answer:
mihalych1998 [28]3 years ago
6 0

Answer:

sorry

Explanation:

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Where are stars that are in their giant or super giant stages located on the Hertzsprung-Russell diagram?
maxonik [38]
I’m pretty sure it’s A) upper right!
3 0
3 years ago
Fred mixes a solution using two types of solutions: 0.60 liters containing 10% alcohol and 0.40 liters containing 35% alcohol. W
insens350 [35]

The alcohol concentration of the mixed solution is 20%

Simplification :

Based on the given condition, formulate :

35% ×0.40 + 0.6 ×10% ÷{ 0.4+0.6}

Calculate the product :\frac{0.14+0.06}{0.4 + 0.6}

Calculate the sum or difference : \frac{0.2}{1}

Any fraction with denominator 1 is equal to numerator : 0.2

Multiply a number to both numerator, denominator : 0.2 ×\frac{100}{100}

Calculate the product or quotient : \frac{20}{100}

A fraction with denominator equals to 100 to a percentage 20%.

How do you find the concentration of a mixed solution?

In general when your are mixing two different concentrations together first calculate number of moles for each solution (n=CV ,V-in liter) then add them together it will be total moles,then concentration of mixture will be = total moles / total volume(liter).

Learn more about concentration of alcohol :

brainly.com/question/13220698

#SPJ4

5 0
2 years ago
When 40.5 g of Al and 212.7 g of Cl2 combine in the reaction: 2 Al (s) + 3 Cl2 (g) --> 2 AlCl3 (s) c) How many moles of the e
sineoko [7]

Answer:

The answer to your question is 1.49 mol of Cl₂  

Explanation:

Data

mass of Al = 40.5 g

mass of Cl₂ = 212.7 g

moles of excess reactant = ?

- Balanced chemical reaction

                2 Al(s)  +  3Cl₂(g)  ⇒   2AlCl₃

Process

a) Calculate the molar mass of the reactants  

molar mass of Al = 2 x 26.98 = 53.96 g

molar mass of Cl₂ = 6 x 35.45 = 212.7 g

b) Calculate the theoretical proportion  Al/Cl₂ = 53.96/212.7 = 0.254

   Calculate the experimental proportion Al/Cl₂ = 40.5/212.7 = 0.19

As the experimental proportion is lower than the theoretical proportion we conclude that the limiting reactant is Aluminum.

c) Calculate the grams of excess reactant

                    53.96 g of Al ------------------ 212.7 g of Cl₂

                     40.5 g of Al -------------------  x

                      x = (40.5 x 212.7) / 53.96

                      x = 8614.35 / 53.96

                      x = 159.64 g of Cl₂

Excess Cl₂ = 212.7 - 159.64

                  = 53.057 g

d) Calculate the moles of Cl

                       35.45 g of Cl ----------------- 1 mol

                       53.057 g of Cl ---------------  x

                        x = (53.057 x 1)/35.45

                       x = 1.49 mol of Cl₂                    

6 0
3 years ago
Read 2 more answers
When 4.50 L of hydrogen gas react with an excess of nitrogen gas at standard temperature and pressure, how many liters of ammoni
VARVARA [1.3K]

Answer:

           3.0 L of NH₃

Solution:

The equation is as follow,

                                    N₂  +  3 H₂     →       2 NH₃

According to equation,

          67.2 L (3 mole) H₂ at STP produces  =  44.8 L (3 mole) of NH₃

So,

                            4.50 L of H₂ will produce  =  X L of NH₃

Solving for X,

                     X  =  (4.50 L × 44.8 L) ÷ 67.2 L

                     X  =  3.0 L of NH₃

5 0
3 years ago
A liquid that occupies a volume of 8.2 L has a mass of 5.6 kg ehat is the density of the liquid in kg/l
BaLLatris [955]
Hey there!

Mass = 5.6 Kg

Volume =8.2 L

D = m / V

D = 5.6 / 8.2

D = 0.6829 Kg/L

hope this helps!
4 0
3 years ago
Read 2 more answers
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