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3 years ago

The table below gives the numbers of protons, electrons, and neutrons in

Chemistry

1 answer:

Dominik [7]3 years ago

7 0

Answer:

i may be smart... but right now all I want is points

Explanation:

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What is the weight on earth of a book with a mass of 1.5kg

Marta_Voda [28]

1.5x10
=15N

sorry if im wrong

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3 years ago

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A student ran the following reaction in the laboratory at 311 K:CH4(g) + CCl4(g) 2CH2Cl2(g)When she introduced 4.10×10-2 moles o

statuscvo [17]

Answer: The value of $K_{eq}$ is 0.044

Explanation:

We are given:

Initial moles of methane = $4.10\times 10^{-2}mol=0.0410moles$

Initial moles of carbon tetrachloride = $6.51\times 10^{-2}mol=0.0651moles$

Volume of the container = 1.00 L

Concentration of a substance is calculated by:

$\text{Concentration}=\frac{\text{Number of moles}}{\text{Volume}}$

So, concentration of methane = $\frac{0.0410}{1.00}=0.0410M$

Concentration of carbon tetrachloride = $\frac{0.0651}{1.00}=0.0651M$

The given chemical equation follows:

$CH_4(g)+CCl_4(g)\rightleftharpoons 2CH_2Cl_2(g)$

Initial: 0.0410 0.0651

At eqllm: 0.0410-x 0.0651-x 2x

We are given:

Equilibrium concentration of carbon tetrachloride = $6.02\times 10^{-2}M=0.0602M$

Evaluating the value of 'x', we get:

$\Rightarrow (0.0651-x)=0.0602\\\\\Rightarrow x=0.0049M$

Now, equilibrium concentration of methane = $0.0410-x=[0.0410-0.0049]=0.0361M$

Equilibrium concentration of $CH_2Cl_2=2x=[2\times 0.0049]=0.0098M$

The expression of $K_{eq}$ for the above reaction follows:

$K_{eq}=\frac{[CH_2Cl_2]^2}{[CH_4]\times [CCl_4]}$

Putting values in above expression, we get:

$K_{eq}=\frac{(0.0098)^2}{0.0361\times 0.0603}\\\\K_{eq}=0.044$

Hence, the value of $K_{eq}$ is 0.044

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3 years ago

What is the name of CF4?.

Mumz [18]

Answer:

please mark me as brainlest

Explanation:

carbon fluoride is the answers

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2 years ago

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Which has a higher boiling point hcl or hi

Likurg_2 [28]

HI.

Hope this helps!

-Payshence

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3 years ago

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How many miles are in 215 grams of water

Irina18 [472]

You're off to a good start, now find the mass of H2O and put it under I mol,

then multiply 1 mol over the mass of H2O by 215 grams

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3 years ago