All categories

3 years ago

How do catalysts increase the rate of a chemical reaction?

Chemistry

2 answers:

bogdanovich [222]3 years ago

7 0

A, They Lower The Activation Energy.

morpeh [17]3 years ago

5 0

Yup, if you add a catalyst the activation energy needed to overcome is lower to form a reaction.

You might be interested in

How many grans of NaoH Are needed to neutralize grans of H2So4

user100 [1]

Answer :]

to convert from g NaOH to mol NaOH. = 1.48 g NaOH are needed to neutralize the acid.

5 0

2 years ago

The element copper has 29 protons. What is the atomic number of copper?

stiks02 [169]

The atomic number of copper is 29.

Hope this helps and if it does, don't be afraid to rate my answer as well as maybe give it a "Thanks"? (Or even better a "Brainliest"). And if it’s not correct, I am sorry for wasting your time, and good luck finding the correct answer :)

8 0

3 years ago

Read 2 more answers

2. Fluorine gas exerts a pressure of 1.2 atm. When the

Mariana [72]

Answer:

look at the photo........................

6 0

2 years ago

What is a toxic chemical?

My name is Ann [436]

Answer:any substance which may be harmful to the environment or hazardous to your health if inhaled, ingested or absorbed through the skin.

Explanation:

8 0

3 years ago

A 44% wt/wt solution of H2SO4 has a density of 1.343g/ml. What mass of H2SO4 is 60ml of this solution?

horsena [70]

<u>Answer:</u> The mass of sulfuric acid present in 60 mL of solution is 34.1 grams

<u>Explanation:</u>

We are given:

44 % (m/m) solution of sulfuric acid. This means that 44 grams of sulfuric acid is present in 100 grams of solution.

To calculate volume of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of solution = 1.343 g/mL

Mass of solution = 100 g

Putting values in above equation, we get:

$1.343g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{100g}{1.343g/mL}=77.46mL$

To calculate the mass of sulfuric acid present in 60 mL of solution, we use unitary method:

In 77.46 mL of solution, mass of sulfuric acid present is 44 g

So, in 60 mL of solution, mass of sulfuric acid present will be = $\frac{44g}{77.46mL}\times 60mL=34.1g$

Hence, the mass of sulfuric acid present in 60 mL of solution is 34.1 grams

3 0

3 years ago