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Kruka [31]
3 years ago
7

How do catalysts increase the rate of a chemical reaction?

Chemistry
2 answers:
bogdanovich [222]3 years ago
7 0
A, They Lower The Activation Energy.
morpeh [17]3 years ago
5 0
Yup, if you add a catalyst the activation energy needed to overcome is lower to form a reaction.

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How many grans of NaoH Are needed to neutralize grans of H2So4​
user100 [1]

Answer :]

to convert from g NaOH to mol NaOH. = 1.48 g NaOH are needed to neutralize the acid.

5 0
2 years ago
The element copper has 29 protons. What is the atomic number of copper?
stiks02 [169]
The atomic number of copper is 29.

Hope this helps and if it does, don't be afraid to rate my answer as well as maybe give it a "Thanks"? (Or even better a "Brainliest"). And if it’s not correct, I am sorry for wasting your time, and good luck finding the correct answer :)


8 0
3 years ago
Read 2 more answers
2. Fluorine gas exerts a pressure of 1.2 atm. When the
Mariana [72]

Answer:

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6 0
2 years ago
What is a toxic chemical?
My name is Ann [436]

Answer:any substance which may be harmful to the environment or hazardous to your health if inhaled, ingested or absorbed through the skin.

Explanation:

8 0
3 years ago
A 44% wt/wt solution of H2SO4 has a density of 1.343g/ml. What mass of H2SO4 is 60ml of this solution?
horsena [70]

<u>Answer:</u> The mass of sulfuric acid present in 60 mL of solution is 34.1 grams

<u>Explanation:</u>

We are given:

44 % (m/m) solution of sulfuric acid. This means that 44 grams of sulfuric acid is present in 100 grams of solution.

To calculate volume of a substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of solution = 1.343 g/mL

Mass of solution = 100 g

Putting values in above equation, we get:

1.343g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{100g}{1.343g/mL}=77.46mL

To calculate the mass of sulfuric acid present in 60 mL of solution, we use unitary method:

In 77.46 mL of solution, mass of sulfuric acid present is 44 g

So, in 60 mL of solution, mass of sulfuric acid present will be = \frac{44g}{77.46mL}\times 60mL=34.1g

Hence, the mass of sulfuric acid present in 60 mL of solution is 34.1 grams

3 0
3 years ago
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