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3 years ago

How do catalysts increase the rate of a chemical reaction?

Chemistry

2 answers:

bogdanovich [222]3 years ago

7 0

A, They Lower The Activation Energy.

morpeh [17]3 years ago

5 0

Yup, if you add a catalyst the activation energy needed to overcome is lower to form a reaction.

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the men's world record for swimming 1500.0 m in a long course pool (as of 2007) is 14 min 34.56 s. At this rate, how many second

Lyrx [107]

140 s. It would take 140 s to swim 0.150 mi .

Step 1. Convert the time to seconds

Time = 14 min × (60 s/1 min) + 34.56 s = 840 s + 34.56 s = 874.56 s

Step 2. Convert miles to metres

Distance = 0.150 mi × (1609.3 m/1 mi) = 241.4 m

Step 3. Calculate the time to swim 241.4 m

Time = 241.4 m × (874.56 s/1500 m) = 140 s

(As of 2012, the men’s freestyle record for 1500 m was 14:31.02.)

5 0

3 years ago

How did Bohr solve the contradiction with physics with his model of an atom

daser333 [38]

Answer:

He used Velocity and Radius.

Explanation:

The uncertainty truths contradicts Bohr's thoughts of electrons.

4 0

3 years ago

A rigid vessel contains 3.98 kg of refrigerant-134a at 700 kPa and 60°C. Determine the volume of the vessel and the total intern

Arada [10]

Answer: The volume of the vessel is $0.1542m^3$ and total internal energy is 162.0 kJ.

Explanation:

To calculate the volume of water, we use the equation given by ideal gas, which is:

$PV=nRT$

or,

$PV=\frac{m}{M}RT$

where,

P = pressure of container = 700 kPa

V = volume of container = ? L

m = Given mass of R-134a = 3.98 kg = 3980 g (Conversion factor: 1kg = 1000 g)

M = Molar mass of R-134a = 102.03 g/mol

R = Gas constant = $8.31\text{L kPa }mol^{-1}K^{-1}$

T = temperature of container = $60^oC=[60+273]K=333K$

Putting values in above equation, we get:

$700kPa\times V=\frac{3980g}{102.03g/mol}\times 8.31\text{L kPa }\times 333K\\\\V=154.21L$

Converting this value into $m^3$ , we use the conversion factor:

$1m^3=1000L$

So, $\Rightarrow (\frac{1m^3}{1000L})\times 154.21L$

$\Rightarrow 0.1542m^3$

To calculate the internal energy, we use the equation:

$U=\frac{3}{2}nRT$

or,

$U=\frac{3}{2}\frac{m}{M}RT$

where,

U = total internal energy

m = given mass of R-134a = 3.98 kg = 3980 g (Conversion factor: 1kg = 1000g)

M = molar mass of R-134a = 102.03 g/mol

R = Gas constant = $8.314J/K.mol$

T = temperature = $60^oC=[60+273]K=333K$

Putting values in above equation, we get:

$U=\frac{3}{2}\times \frac{3980g}{102.03g/mol}\times 8.314J/K.mol\times 333K\\\\U=161994.6J$

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, 161994.6 J = 162.0 kJ

Hence, the volume of the vessel is $0.1542m^3$ and total internal energy is 162.0 kJ.

6 0

3 years ago

An object weighting 9.6 grams is placed in a graduated cylinder displacing the volume from 10.0mL to 13.2 mL

grigory [225]

The volume of object is 3.2 ml

<h3>Explanation:</h3>

Given:

Mass of the object = M = 9.6 g

Initial volume of liquid: $V_1 = 10.0\ ml$

Final volume of liquid after displacement: $V_2 = 13.2\ ml$

Total volume of the displaced object inside a graduating cylinder will be given as difference between the final volume and initial volume of the expanding object.

$V = V_2-V_1 = 13.2 -1 0.0 = 3.2\ ml$

V = 3.2 ml

3 0

3 years ago

What does NA means in chemistry form

Amanda [17]

It’s is sodium, the 11th element on the periodic table.

6 0

3 years ago

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