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3 years ago

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Which rule is used for writing the name of an ionic base?

2 answers:

Solnce55 [7]3 years ago

7 0

<span>Binary Molecular Compounds</span>

zlopas [31]3 years ago

7 0

When you name ionic compounds, you write the name of the metal first and then the nonmetal. Suppose that you want to name the compound that results from the reaction of lithium and sulfur. You first write the name of the metal, lithium, and then write the name of the nonmetal, adding an -ide ending so that sulfur becomes sulfide.

Ionic compounds involving polyatomic ions follow the same basic rule: Write the name of the metal first, and then simply add the name of the nonmetal (with the polyatomic anions, it is not necessary to add the -ide ending).

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STALIN [3.7K]

Answer: The space occupied by the gas at 400 torr and $25^{o}C$ is 250 mL.

Explanation:

Given: $V_{1}$ = 250 mL, $P_{1}$ = 800 torr, $T_{1} = 50^{o}C$

$V_{2} = ?$ , $P_{2}$ = 400 torr, $T_{2} = 25^{o}C$

Formula used is as follows.

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}$

Substitute the values into above formula as follows.

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{800 torr \times 250 mL}{50^{o}C} = \frac{400 torr \times V_{2}}{25^{o}C}\\V_{2} = 250 mL$

Thus, we can conclude that space occupied by the gas at 400 torr and $25^{o}C$ is 250 mL.

7 0

2 years ago

Match each decimal number to the correct scientific notation.

Effectus [21]

3.07 × 10^4=30,700

3.07 × 10^-4=0.000307

3.07 × 10^-6=0.00000307

3.07 × 10^6=3,070,000

5 0

2 years ago

Read 2 more answers

What does the atomic mass of a neutral atom tell you?

ExtremeBDS [4]

Answer:

yes

Explanation:

6 0

2 years ago

What volume of oxygen at STP is requieres for the complete combustion of 100.50 mL of C2H2

malfutka [58]

The volume of oxygen at STP required would be 252.0 mL.

<h3>Stoichiometic problem</h3>

The equation for the complete combustion of C2H2 is as below:

$2C_2H_2 + 5O_2 --- > 4CO_2 + 2H_2O$

The mole ratio of C2H2 to O2 is 2:5.

1 mole of a gas at STP is 22.4 L.

At STP, 100.50 mL of C2H2 will be:

100.50 x 1/22400 = 0.0045 mole

Equivalent mole of O2 according to the balanced equation = 5/2 x 0.0045 = 0.01125 moles

0.01125 moles of O2 at STP = 0.01125 x 22400 = 252.0 mL

Thus, 252.0 mL of O2 gas will be required at STP.

More on stoichiometric problems can be found here: brainly.com/question/14465605

#SPJ1

7 0

1 year ago

What is the total mass of oxygen contained in 8.20g of benzoic acid (C6H5COOH)

VashaNatasha [74]

Answer:

Mass of oxygen = 2.2 g

Explanation:

Given data:

Mass of benzoic acid= 8.20 g

Mass of oxygen= ?

Solution:

Molar mass of oxygen = 16×2 g/mol

Molar mass of C₆H₅COOH = 7×12 + 1×6 + 2×16

Molar mass of C₆H₅COOH = 84 + 6 + 32

Molar mass of C₆H₅COOH = 122g/mol

Mass of oxygen in 8.20 g of C₆H₅COOH :

Mass of oxygen = 32 g.mol⁻¹/122 g.mol⁻¹ × 8.20 g

Mass of oxygen = 2.2g

4 0

2 years ago