Answer:
80.0 g Na and 20.0 g N2.
Explanation:
This means the limiting reactant determines the maximum mass of the product formed.
There is no element in 2s3
<u>Given:</u>
Mass of MgBr2 = 0.500 g
<u>To determine:</u>
Number of anions in 0.500 g MgBr2
<u>Explanation:</u>
Molar mass of MgBr2 = 24 + 2 (80) = 184 g/mol
Moles of MgBr2 = 0.500 g/184 g.mol-1 = 0.00271 moles
Based on stoichiometry-
1 mole of MgBr2 has 1 mole of Mg2+ cations and 2 moles of Br- anions
Therefore, 0.00271 moles of MgBr2 will have: 2 * 0.00271 = 0.00542 moles of Br-
Now,
1 mole of Br- contains 6.023 * 10²³ anions
0.00542 moles of Br- contain: 0.00542 * 6.023*10²³ = 3.264*10²¹ anions
Ans: There are 3.264*10²¹ anions in 0.5 g of MgBr2
Answer:
The two types of collisions are :
Type a)
<u>Elastic collision</u>
Type b)
<u>Inelastic collision</u>
Explanation:
Collision : It is the event when two bodies collide with each other for small period of time.
During collision , the bodies exert force to each other.
Example :
When boxer hits with punches .
When bat hits the ball in cricket match.
So, collision is short duration interaction of two objects. When the objects collides , there is change in their velocity.
All collision follow law of conservation of momentum . Their type is decided by , whether they follow conservation of energy also.
<u>Compare and contrast the two types</u>
a) Elastic collision : Those collision in which no loss or gain of kinetic energy will occur. They follow conservation of kinetic energy. Example : ideal gaseous molecule
b) Inelastic collision : Those collision in which Change in kinetic energy will occur. They do not follow conservation of kinetic energy.Almost all conservation are inelastic.
Here Kinetic energy get converted into other form of energy.