F = applied force on the wheelbarrow in forward direction = 600 N
f = frictional force pushing in backward direction of wheelbarrow = ?
m = mass of the wheelbarrow = 28 kg
Since wheelbarrow moves forward at a constant velocity
a = acceleration of the wheelbarrow in forward direction = 0 m/s²
force equation for the motion of wheelbarrow in forward direction is given as
F - f = ma
inserting the above values in the formula
600 - f = (28) (0)
600 - f = 0
f = 600 N
hence the frictional force comes out to be 600 N
Answer:
b) Vectors A and B are in the same direction.
Explanation:
To understand this problem we will say that vector A has a magnitude of 5 units and vector B a magnitude of 3 units. In the subtraction of vectors the initial parts of vectors always bind together. And the vector resulting from the subtraction is traced from the end of the second vector (B) to the end of the first vector (A).
The length of the resultant vector will be 5 - 3 = 2
In the attached image, we analyze case a), b), and d)
For a)
As we can see in the attached image the resultant vector has a length of 8 units.
For d)
As we can see in the attached image the resultant vector has a length of 5.83 units.
For b)
The resultant vector has a length of 2 units.
Therefore the case given in b) is true
Answer:
Average speed, 
Explanation:
Given:
- Initial speed, u=40 cm/s
- final speed , v=20 cm/s
- Time taken, t=5 s
<u>First case</u>
Using equation of motion we have

Now using,

now putting the value of a in first equation we get

<u>Second case</u>
Acceleration
Time taken 
using equation of motion in one Dimension we have

Average speed is equal to total distance travelled per unit total time taken

Answer: When an earthquake occurs energy is transferred, from where the rocks break, and travels throughout the world. The bigger the quake the further from the epicentre the waves will travel. There are four types of earthquake wave generated during an earth quake
Explanation: