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Anna [14]
3 years ago
12

Where does the negative charge come from?

Physics
2 answers:
azamat3 years ago
8 0

negative charge come from the gain of electron

nlexa [21]3 years ago
8 0

Answer:

An electrical charge is created when electrons are transferred too or removed from an object. Because electrons have a negative charge, when they are added to an object, it becomes negatively charged. When electrons are removed from an object, it becomes positively charged.

From G00gle

Explanation:

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The y-axis on a distance-time graph would be ____________. time distance speed
natita [175]

Answer:

Distance

Explanation:

distance is in vertical axis,or y-axis and time is on the horizontal axis,or x-axis.

7 0
3 years ago
A pen rolls off a 0.55–meter high table with an initial horizontal velocity of 1.2 meters/second. At what horizontal distance fr
NARA [144]
To find the horizontal distance multiple the horizontal velocity by the time. Since there is no given time it must be calculated using kinematic equation.

Y=Yo+Voyt+1/2at^2
0=.55+0+1/2(-9.8)t^2
-.55=-4.9t^2
sqrt(.55/4.9)=t
t=0.335 seconds

Horizontal distance
=0.335s*1.2m/s
=0.402 meters
8 0
3 years ago
Write any three reasons to separate the mixtures?​
dmitriy555 [2]

Answer:

people separate mixtures in order to ger a specific substance that they need. 2. the other thing people separate mixtures to remove the unrequired components. 3.To get a pure substance

Explanation:

hope this helps probably don't because you asked this a week ago but have a good day :) ❤

5 0
3 years ago
The velocity of the transverse waves produced by an earthquake is 5.05 km/s, while that of the longitudinal waves is 8.585 km/s.
sattari [20]

Answer:

d=691.71km

Explanation:

The time lag between the arrival of transverse waves and the arrival of the longitudinal waves is defined as:

t=\frac{d}{v_t}-\frac{d}{v_l}

Here d is the distance at which the earthquake take place and v_t, v_l is the velocity of the transverse waves and longitudinal waves respectively. Solving for d:

t=d(\frac{1}{v_t}-\frac{1}{v_l})\\d=\frac{t}{\frac{1}{v_t}-\frac{1}{v_l}}\\d=\frac{56.4s}{\frac{1}{5.05\frac{km}{s}}-\frac{1}{8.585\frac{km}{s}}}\\d=691.71km

8 0
3 years ago
Is it true that at freezing point particle are vibrating so fast they break free?
kondor19780726 [428]
It is false. The effect of freezing is almost the exact opposite
4 0
4 years ago
Read 2 more answers
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