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2 years ago

A 5kg cart moving to the right with a velocity of 16 m/s collides with a concrete wall and

Physics

1 answer:

Kryger [21]2 years ago

8 0

Explanation:

mass, m = 5kg

initial velocity, u = 16m/s

final velocuty, v = -22m/s

change in momentum, ∆p = ?

∆p = m (v-u)

5(-22-16)

5(38)

∆p = 190kgm/s

check the calculations!

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Plz do all of it i will give brainlest and thanks to best answer plz do it right

AlladinOne [14]

The answer is a rainforest I’m pretty sure

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2 years ago

Read 2 more answers

An airplane during departure has a constant acceleration of 3 m / s².

Rama09 [41]

Constant acceleration of plane = 3m/s²

a) Speed of the plane after 4s

Acceleration = speed/time

3m/s² = speed/4s

S = 12m/s

The speed of the plane after 4s is 12m/s.

b) Flight point will be termed as the point the plane got initial speed, u, 20m/s

Find speed after 8s, v

a = 3m/s²

from,

a = v - u

3 = v - 20

24 = v - 20

v = 44m/s

After 8s the plane would've 44m/s speed.

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2 years ago

while spinning in a centrifuge a 70.0 kg astronaut experiences an acceleration of 5.00 g, or five times the acceleration due to

ollegr [7]

Answer:

Explanation:

70.0(5.00)(9.81) = 3,433.5 = 3430 N

4 0

2 years ago

a) What is the average useful power output of a person who does6.00×10^6Jof useful work in 8.00 h? (b) Working at this rate, how

NARA [144]

Answer:

208.33 W

141.26626 seconds

Explanation:

E = Energy = $6\times 10^6\ J$

t = Time taken = 8 h

m = Mass = 2000 kg

g = Acceleration due to gravity = 9.81 m/s²

h = Height of platform = 1.5 m

Power is obtained when we divide energy by time

$P=\frac{E}{t}\\\Rightarrow P=\frac{6\times 10^6}{8\times 60\times 60}\\\Rightarrow P=208.33\ W$

The average useful power output of the person is 208.33 W

The energy in the next part would be the potential energy

The time taken would be

$t=\frac{E}{P}\\\Rightarrow t=\frac{mgh}{208.33}\\\Rightarrow t=\frac{2000\times 9.81\times 1.5}{208.33}\\\Rightarrow t=141.26626\ s$

The time taken to lift the load is 141.26626 seconds

5 0

3 years ago

What is the density of a piece of quartz with a mass of 30g and a volume of 6cm^3

FromTheMoon [43]

Answer:

$\boxed {\boxed {\sf d= 5 \ g/cm^3}}$

Explanation:

Density can be found by dividing the mass by the volume.

$d=\frac{m}{v}$

The mass of the quartz is 30 grams and the volume is 6 cubic centimeters.

$m=30 \ g \\v= 6 \ cm^3$

Substitute the values into the formula.

$d=\frac{30 \ g}{6 \ cm^3}$

Divide.

$d= 5 \ g/cm^3$

The density of this piece of quartz is 5 grams per cubic centimeter.

7 0

3 years ago