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3 years ago

What of the following describes how an organism responds to external stimuli?

Chemistry

1 answer:

Pani-rosa [81]3 years ago

8 0

Yes, your answer should be and is <span>A. a mouse runs away from a cat that is chasing it.

Hope this helped!</span>

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What is the carrier molecule

creativ13 [48]

Explanation:

A carrier molecule is, A role in transporting electrons through the electron transport chain carrier molecules are usually poetries bond to a non-protein group they can undergo oxidation and reduction

6 0

3 years ago

Read 2 more answers

Which type of reproduction will result in identical copies of itself and why?

Dennis_Churaev [7]

Answer:

Mitosis is a method of cell division in which a cell divides and produces identical copies of itself. The primary mechanism by which organisms generate new cells is through cell division. During this process, a single "parent" cell will divide and produce identical "daughter" cells.

Explanation:

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3 years ago

The diffusion flux is defined as: a) Mass, per unit surface area, per unit time b) Surface area, per unit time c) Time, per unit

s2008m [1.1K]

Answer:

The correct answer is option a.

Explanation:

Diffusion flux is defined as movement of mas of atoms diffusing through the unit area in per unit time.It measured in ( $kg/m^2 s$ ).

$J=\frac{1}{A}\frac{dM}{dt}$

J = diffusion flux

A = Unit area A through which atoms moves.

M = mass of atoms passes in t interval of time.

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4 years ago

Is energy from the light source conduction convention or radiation

tiny-mole [99]

Energy from a light source is known as radiation.

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3 years ago

Using the appropriate Ksp values, find the concentration of K+ ions in the solution at equilibrium after 600 mL of 0.45 M aqueou

Alekssandra [29.7K]

Answer:

[K⁺] = 0.107 M

[OH⁻] = 1.13 × 10⁻⁹ M

Explanation:

600 mL of 0.45 M Cu(NO3)2 gives equal mole of Cu²⁺ and (NO₃)²⁻

⇒ 0.45 × 600 × 10⁻³

= 0.27 moles of Cu²⁺ and (NO₃)²⁻

450 mL of 0.25 M KOH gives equal moles of K⁺ and OH⁻

⇒ 0.25 × 450 × 10⁻³

= 0.1125 moles of K⁺ and OH⁻

Now after mixing 0.1125 moles of OH⁻ precipitates 0.05625 moles of Cu²⁺ (because 1 Cu²⁺ needs 2 OH⁻)

Therefore , moles of remaining Cu²⁺ = 0.27 - 0.05625

=0.21375 moles which is equal to :

⇒ 0.21375/(( 600+450))× 10⁻³

= 0.21375/1050 × 10⁻³

= 0.20357 M

Given that :

(Ksp for Cu(OH)2 is 2.6 × 10⁻¹⁹)

We know that , Ksp = [Cu²⁺][OH⁻]²

2.6 × 10⁻¹⁹ = 0.20357 × [OH⁻]²

[OH⁻]² = 2.6 × 10⁻¹⁹/0.20357

[OH⁻] = 1.13 × 10⁻⁹ M

[K⁺] = moles of K⁺ /total volume

[K⁺] = 0.1125 / 1050 × 10⁻³

[K⁺] = 0.107 M

6 0

3 years ago