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3 years ago

Match what is seen through a telescope with the information that is learned from it.

Physics

1 answer:

dlinn [17]3 years ago

4 0

I don’t want to know that I have to do homework homework and homework homework done homework homework and homework I’m not tired but yes and I will just go watch the park and bath bath green bath

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If the 15.0 cm string is shorter than the 30.0 cm string.

Margaret [11]

Answer:

option c) 2 is the right answer

7 0

3 years ago

A hiker walks due east for a distance of 25.5 km from her base camp. On the second day, she walks 41.0 km northwest till she dis

GarryVolchara [31]

Resultant displacement is 29.2 km at $83.1^{\circ}$ north of west

Explanation:

To solve the problem, we have to use the rules of vector addition, resolving first each vector along the x- and y- direction.

Taking east as positive x direction and north as positive y- direction, we have:

- First displacement is 25.5 km east, therefore its components are

$A_x = 25.5 km\\A_y = 0 km$

- Second displacement is 41.0 km northwest, so its components are

$B_x = (41.0)cos(135^{\circ})=-29.0 km\\B_y =(41.0)sin(135^{\circ})=29.0 km$

So, the components of the resultant displacement are

$R_x=A_x+B_x=25.5+(-29.0)=-3.5 km\\R_y=A_y+B_y=0+29.0=29.0 km$

And so, the magnitude is calculated using Pythagorean's theorem:

$R=\sqrt{R_x^2+R_y^2}=\sqrt{(-3.5)^2+(29.0)^2}=29.2 km$

And the direction is given by

$\theta=tan^{-1}(\frac{R_y}{|R_x|})=tan^{-1}(\frac{29.0}{3.5})=83.1^{\circ}$

Where the angle is measured from the west direction, since Rx is negative.

Learn more about displacement:

brainly.com/question/3969582

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3 0

3 years ago

two coils close to each other have a mutual inductance of 32 mh. if the current in one coil decays according to , where i0

Harlamova29_29 [7]

The EMF induced in the second coil is 43 Volts.

Michael Faraday was the first to discover electromagnetic induction back in the 1830s. Faraday discovered that moving a permanent magnet in and out of a coil or a single loop of wire caused an electromotive force, or EMF—otherwise known as a voltage—to be produced.

Changing magnetic flux results in varied currents flowing through the coil, which in turn generates its own magnetic field. This self-induced EMF opposes the change that is creating it, and the stronger the opposing EMF is, the faster the rate at which the current is changing. According to Lenz's law, this self-induced EMF will oppose the change in current in the coil, and because of its orientation, it is typically referred to as a back-EMF.

To learn more about EMF please visit-

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3 0

2 years ago

A skater with an initial speed of 7.30 m/s stops propelling himself and begins to coast across the ice, eventually coming to res

Rufina [12.5K]

Answer:

a. a= 1.029 ms⁻²

b. S=25.89 m

Explanation:

given

initial speed is u = 7.30 m/sec

final speed is v = 0 m/sec

mu_k = 0.105

kinetic frictional force is Fk = mu_k×m×g

mu_k×m×g = m×a

m cancels

mu_k×g = a

deccelaration a = mu_k×g = 0.105×9.8 =1.029 ms⁻²

b) using v²-u² = 2aS

0²-7.3² = -2×1.029×S

53.29=2.058×S

S = 53.29/2.058

S=25.89 m

6 0

3 years ago

slader How much energy is required to move a 1040 kg object from the Earth's surface to an altitude four times the Earth's radiu

andrew-mc [135]

Answer:

ΔU = 5.21 × 10^(10) J

Explanation:

We are given;

Mass of object; m = 1040 kg

To solve this, we will use the formula for potential energy which is;

U = -GMm/r

But we are told we want to move the object from the Earth's surface to an altitude four times the Earth's radius.

Thus;

ΔU = -GMm((1/r_f) - (1/r_i))

Where;

M is mass of earth = 5.98 × 10^(24) kg

r_f is final radius

r_i is initial radius

G is gravitational constant = 6.67 × 10^(-11) N.m²/kg²

Since, it's moving to altitude four times the Earth's radius, it means that;

r_i = R_e

r_f = R_e + 4R_e = 5R_e

Where R_e is radius of earth = 6371 × 10³ m

Thus;

ΔU = -6.67 × 10^(-11) × 5.98 × 10^(24)

× 1040((1/(5 × 6371 × 10³)) - (1/(6371 × 10³))

ΔU = 5.21 × 10^(10) J

7 0

3 years ago