I really need help on this!
2 answers:
You might be interested in
Answer:
Therefore, the horizontal displacement of end F of rod EF is 0.4797 mm
Explanation:
solution is mentioned in steps.
Answer:
Explanation:
k_max = 26.9 w/mk
k_min = 22.33 w/mk
Explanation:
a) the maximum thermal conductivity is given as
K_MAX = k_m v_m + k_p v_p
where k_m is thermal conductvitiy of metal
k_p is thermal conductvitiy of carbide
v_m = proportion of metal in the cement = 0.15
v_p = proportion of carbide in the cement = 0.85
= 66*0.15 + 20*0.85
k_max = 26.9 w/mk
b) the minimum thermal conductivity is given as
= \frac{20*66}{20*0.15 +66*0.85}
k_min = 22.33 w/mk
Answer:
CDI= 1.393 × 10^-3 mg/kg.d
Explanation:
The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.
