To solve this problem it is necessary to apply the concepts related to temperature stagnation and adiabatic pressure in a system.
The stagnation temperature can be defined as
Where
T = Static temperature
V = Velocity of Fluid
Specific Heat
Re-arrange to find the static temperature we have that
Now the pressure of helium by using the Adiabatic pressure temperature is
Where,
= Stagnation pressure of the fluid
k = Specific heat ratio
Replacing we have that
Therefore the static temperature of air at given conditions is 72.88K and the static pressure is 0.399Mpa
<em>Note: I took the exactly temperature of 400 ° C the equivalent of 673.15K. The approach given in the 600K statement could be inaccurate.</em>
Answer:
V1 = 1.721 * V2
Explanation:
To start with, we assume that both lift forces are equal, such that
L2 = L1
1 is that of the level at 10000 m, and 2 is that of the level at sea level.
Next, we try and substitute the general formula for both forces such that
C(l).ρ1/2.V1².A = C(l).ρ2/2.V2².A
On further simplification, we have
ρ1.V1² = ρ2.V2², making V1 subject of formula, we have
V1 = √(ρ2/ρ1). V2²
Using the values of density for air at 10000 m and at sea level(source is US standard atmosphere), we have
V1 = √(1.225/0.4135) * V2
V1 = √2.9625 * V2
V1 = 1.721 * V2
Answer:
C.
Explanation:
Natural language processing or NLP can be defined as an artificial intelligence that aids computers to understand, interpret, and manipulate human language. NLP is subfiled of many disciplines, for instance, artifical intelligence, linguistics, computer science, etc. NLP helps computers to interact with humans in their own language.
So, the easier way through which people can communicate with computers apart from GUI is NLP. Thus option C is correct.
Answer:
Answer: ±0.02 units or 20±0.02 units or 19.98-20.02 units depending on how they prefer its written (typically the first or second one)
Explanation:
says on the sheet. Unless otherwise stated 0.XX = ±0.02 tolerance
(based on image sent in other post)
Answer:
The diameter increases
Explanation:
The expansion in the metal is uniform in every dimension