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AURORKA [14]
3 years ago
6

A three-point bending test is performed on a glass specimen having a rectangular cross section of height d = 5.4 mm (0.21 in.) a

nd width b = 12 mm (0.47 in.); the distance between support points is 43 mm (1.69 in.).(a) Compute the flexural strength if the load at fracture is 292 N (66 lbf). (b) The point of maximum deflection, ?y, occurs at the center of the specimen and is described by where E is the modulus of elasticity and I is the cross-sectional moment of inertia. Compute ?y at a load of 266 N (60 lbf). Assume that the elastic modulus for the glass is 60 GPa. What is the flexural strength of this sample in MPa if the load in part (a) is applied? What is I, the moment of inertia, in m4? What is the deflection, ?y, in mm, at the load given in the problem?

Engineering
1 answer:
Fudgin [204]3 years ago
8 0

Answer:

5.21e-2mm

Explanation:

Please see attachment

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Step 1 of 5

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Eutectic product in Fe-C system is called A. Pearlite B. Bainite C. Ledeburite D. Spheroidite
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3 years ago
A house is losing heat at a rate of 1700 kJ/h per °C temperature difference between the indoor and the outdoor temperatures. Exp
Furkat [3]

Answer:

1700kJ/h.K

944.4kJ/h.R

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Explanation:

Conversions for different temperature units are below:

1K = 1°C + 273K

1R = T(K) * 1.8

= (1°C + 273) * 1.8

1°F = (1°C * 1.8) + 32

Q/delta T = 1700kJ/h.°C

T (K) = 1700kJ/h.°C

= 1700kJ/K

T (R) = 1700kJ/h.°C

= 1700kJ/h.°C * 1°C/1.8R

= 944.4kJ/h.R

T (°F) = 1700kJ/h.°C

= 1700kJ/h.°C * 1°C/1.8°F

= 944.4kJ/h.°F

Note that arithmetic operations like subtraction and addition of values do not change or affect the value of a change in temperature (delta T) hence, the arithmetic operations are not reflected in the conversion. Illustration: 5°C - 3°C

= 2°C

(273+5) - (273+3)

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5 0
3 years ago
You guys are amazing :D
Sloan [31]
Ik i am thank you tho xoxo
3 0
3 years ago
Read 2 more answers
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