1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AURORKA [14]
3 years ago
6

A three-point bending test is performed on a glass specimen having a rectangular cross section of height d = 5.4 mm (0.21 in.) a

nd width b = 12 mm (0.47 in.); the distance between support points is 43 mm (1.69 in.).(a) Compute the flexural strength if the load at fracture is 292 N (66 lbf). (b) The point of maximum deflection, ?y, occurs at the center of the specimen and is described by where E is the modulus of elasticity and I is the cross-sectional moment of inertia. Compute ?y at a load of 266 N (60 lbf). Assume that the elastic modulus for the glass is 60 GPa. What is the flexural strength of this sample in MPa if the load in part (a) is applied? What is I, the moment of inertia, in m4? What is the deflection, ?y, in mm, at the load given in the problem?

Engineering
1 answer:
Fudgin [204]3 years ago
8 0

Answer:

5.21e-2mm

Explanation:

Please see attachment

You might be interested in
8. The operation of a TXV is controlled by the
Katena32 [7]
Answer should be C hopefully
4 0
3 years ago
Discuss the environmental concerns regarding microfibre products
zlopas [31]

I don't know

Explanation:

cfffffffffggg

8 0
3 years ago
A walrus loses heat by conduction through its blubber at the rate of 220 W when immersed in −1.00°C water. Its internal core tem
Llana [10]

Answer:

The average thickness of the blubber is<u> 0.077 m</u>

Explanation:

Here, we want to calculate the average thickness of the Walrus blubber.

We employ a mathematical formula to calculate this;

The rate of heat transfer(H) through the Walrus blubber = dQ/dT = KA(T2-T1)/L

Where dQ is the change in amount of heat transferred

dT is the temperature gradient(change in temperature) i.e T2-T1

dQ/dT = 220 W

K is the conductivity of fatty tissue without blood = 0.20 (J/s · m · °C)

A is the surface area which is 2.23 m^2

T2 = 37.0 °C

T1 = -1.0 °C

L is ?

We can rewrite the equation in terms of L as follows;

L × dQ/dT = KA(T2-T1)

L = KA(T2-T1) ÷ dQ/dT

Imputing the values listed above;

L = (0.2 * 2.23)(37-(-1))/220

L = (0.2 * 2.23 * 38)/220 = 16.948/220 = 0.077 m

7 0
3 years ago
In the dataset "RestRating", the 30 randomly selected patrons give the overall dining experience ratings (Outstanding, Very good
rusak2 [61]

Answer: incomplete question

Explanation:

6 0
3 years ago
Read 2 more answers
Even though jack works in Finance he was not always part of this career cluster. What job might jack have had before working in
Nadya [2.5K]
The answer is either A or B
3 0
3 years ago
Other questions:
  • I want a problems and there solutions of The inception of cavitation?​
    7·1 answer
  • Consider a Carnot refrigeration cycle executed in a closed system in the saturated liquid-vapor mixture region using 0.96 kg of
    11·1 answer
  • Often an attacker crafts e-mail attacks containing malware designed to take advantage of the curiosity or even greed of the reci
    14·1 answer
  • When moving cylinders always remove and make
    8·1 answer
  • On July 23, 1983, Air Canada Flight 143 required 22,300 kg of jet fuel to fly from Montreal to Edmonton. The density of jet fuel
    8·1 answer
  • A steel bar 100 mm (4.0 in.) long and having a square cross section 20 mm (0.8 in.) on an edge is pulled intension with a load o
    6·1 answer
  • I don't know what is this​
    9·1 answer
  • Which of the following would not be considered hot work? A chipping B soldering C
    13·1 answer
  • Pointttttttttttttssssssssssss
    12·1 answer
  • The compression ratio of most small gasoline engines falls between_______and________.
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!