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TiliK225 [7]
3 years ago
12

39. Consider the following molecules:

Chemistry
1 answer:
sweet [91]3 years ago
5 0
I) cc14
ii) h20
iii) i’m not sure

not fully sure but hope this helps!
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How far away is sirius from the sun in inches? ____ in miles? ____
earnstyle [38]

Answer:

the answer is 26.718 inches or

26.76 miles

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3 years ago
What is measurement?...​
Maksim231197 [3]

Explanation:

Measurement is the quantification of attributes of an object or event, which can be used to compare with other objects or events

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3 years ago
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Helium is most likely to behave as an ideal gas when it is under(1) high pressure and high temperature(2) high pressure and low
Mekhanik [1.2K]
Helium is most likely to behave as an ideal gas when it is under 2) High pressure and low temperature. 
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4 years ago
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Write a program that allows the user to enter a number of quarters, dimes, and nickels and then outputs the monetary value of th
miskamm [114]

Answer:

// Program is written in C++ Programming Language

// Comments are used for explanatory purpose

// Program Starts here

#include<iostream>

using namespace std;

int main ()

{

// Declare Variables

int quarter, dimes, nickel, cent;

// Enter values for each

cout<<"Quarter: ";

cin>>quarter;

cout<<"Dimes: ";

cin>>dimes;

cout<<"Nickels: ";

cin>>nickel;

/*

In the United States, these coins have the following values

Quarter = 25 cents

Done = 10 cents

Nickel = 5 cent

Total cent is calculated below

*/

cent = 25 * quarter + 10 * dimes + 5 * nickel;

// Print Total

cout<<"The coins are worth "<<cent<<" cents";

return 0;

}

4 0
3 years ago
Write the net cell equation for this electrochemical cell. phases are optional. do not include the concentrations. sn(s)||sn2+(a
Alchen [17]
E^{o}cell =  E^{o} (Ag+/Ag) -  E^{o}( Sn2+/Sn)
where, E^{o} (Ag+/Ag) = std. reduction potential of Ag+ = 0.7994 v
and Sn2+/Sn = std. reduction potential of Sn2+ = -0.14 v

Thus, E^{o}cell = 0.7994v - (-0.14v) = 0.9394 v

Now, ΔG^{o} = -nFE^{0},
where, n = number of electrons = 2
F = Faraday's constant = 96500 C
∴ΔG^{o} = 2 X 96500 X 0.9394 = -1.18 X 10^{5} J/mol

Now, using Nernst's Equation we have,
[tex]E_{cell} = 0.9394 - \frac{2.303X298}{2X96500}log \frac{0.0115}{ 3.5^{2} }
E_{cell} = 0.9765 v

Finally, ΔG = -nFE = -2 X 96500 X 0.9765 = -1.88 X 10^{5} J/mol

3 0
3 years ago
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