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2 years ago

15

Your bus is traveling 80 km/hr on a class trip to a museum that is 240 kilometers from your school. How long will it take to get

there?

1 answer:

DochEvi [55]2 years ago

7 0

I believe it’s 3 hours since every hour it’s 80km so 3x80 is 240 so it would be 3 hours.

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If the prefix hydro were used to name a ternary acid, what problem would this create when naming chloric acid

Lady_Fox [76]

Hydrochloric acid is a different kind of acid than chloric acid.

Ternary Acids (Oxy-acids) Ternary acids are also referred to as “Oxy-acids. Include hydrogen and oxygen and yet another (normally) nonmetallic detail. Those acids comprise each hydrogen and oxygen but their names make no reference to either hydrogen or oxygen.

A ternary acid is an acid that has the elements hydrogen and oxygen together with every other element, frequently a nonmetal. Or, they comprise hydrogen in addition to a polyatomic ion. An -ate complicated ion is named an -ic acid. as an example, HClO3(aq) consists of the chlorate ion and is known as chloric acid.

A binary acid is an acidic compound that always has hydrogen boned to every other chemical element, most of the time a nonmetal. Ternary acids are acidic compounds that comprise hydrogen and oxygen blended with some other detail. Binary acid has one style of a chemical element (hydrogen bonded to a nonmetal) .

Learn more about the ternary acid here brainly.com/question/13386259

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2 years ago

A galvanic (voltaic) cell has the generic metals X and Y as electrodes. X is more reactive than Y , that is, X more readily reac

koban [17]

Answer:

(a) X electrode

(b) Y electrode

(c) Y electrode

(d) X electrode

(e) Y electrode

Explanation:

<em>A galvanic (voltaic) cell has the generic metals X and Y as electrodes. X is more reactive than Y, that is, X more readily reacts to form a cation than Y does.</em>

In the X electrode occurs the oxidation whereas in the Y electrode occurs the reduction.

Oxidation: X(s) → X⁺ⁿ(aq) + n e⁻

Reduction: Y⁺ˣ(aq) + x e⁻ → Y(s)

<em>Classify the descriptions by whether they apply to the X or Y electrode. </em>

<em>(a) anode.</em> Is where the oxidation takes place (X electrode).

<em>(b) cathode.</em> Is where the reduction takes place (Y electrode).

<em>(c) electrons in the wire flow toward.</em> Electrons in the wire flow toward the cathode (Y electrode).

<em>(d) electrons in the wire flow away.</em> Electrons in the wire flow away from the anode (X electrode).

<em>(e) cations from salt bridge flow toward.</em> Cations from the salt bridge flow toward the cathode (Y electrode) to maintain the electroneutrality.

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3 years ago

Why does chemistry affect all aspests of life and most natural events

miv72 [106K]

Chemistry affects all aspects of life and most natural events because all living and nonliving things are made of matter.

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4 years ago

A certain liquid has a normal boiling point of and a boiling point elevation constant . A solution is prepared by dissolving som

jek_recluse [69]

The question is incomplete, the complete question is:

A certain substance X has a normal freezing point of $-6.4^oC$ and a molal freezing point depression constant $K_f=3.96^oC.kg/mol$ . A solution is prepared by dissolving some glycine in 950. g of X. This solution freezes at $-13.6^oC$ . Calculate the mass of urea that was dissolved. Round your answer to 2 significant digits.

<u>Answer:</u> The mass of glycine that can be dissolved is $1.3\times 10^2g$

<u>Explanation:</u>

Depression in the freezing point is defined as the difference between the freezing point of the pure solvent and the freezing point of the solution.

The expression for the calculation of depression in freezing point is:

$\text{Freezing point of pure solvent}-\text{freezing point of solution}=i\times K_f\times m$

OR

$\text{Freezing point of pure solvent}=\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times w_{solvent}\text{(in g)}}$ ......(1)

where,

Freezing point of pure solvent = $-6.4^oC$

Freezing point of solution = $-13.6^oC$

i = Vant Hoff factor = 1 (for non-electrolytes)

$K_f$ = freezing point depression constant = $3.96^oC/m$

$m_{solute}$ = Given mass of solute (glycine) = ?

$M_{solute}$ = Molar mass of solute (glycine) = 75.07 g/mol

$w_{solvent}$ = Mass of solvent = 950. g

Putting values in equation 1, we get:

$-6.4-(-13.6)=1\times 3.96\times \frac{m_{solute}\times 1000}{75.07\times 950}\\\\m_{solute}=\frac{7.2\times 75.07\times 950}{1\times 3.96\times 1000}\\\\m_{solute}=129.66g=1.3\times 10^2g$

Hence, the mass of glycine that can be dissolved is $1.3\times 10^2g$

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3 years ago

This scientist led a series of experiments that used high speed lightweight atoms called alpha particles to bombard very thin pi

ss7ja [257]

Answer:

B. Ernest Rutherford

Explanation:

Ernest Rutherford was a renown Physicist and a Physics Nobel price winner. In 1911 he proposed the planetary model of atom. When the experiment were conducted he proposed that the atom had a charged nucleus and are surrounded by electrons. This finding was the basis for subsequent studies on radioactivity.

3 0

3 years ago